Answer:
a)
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
a = Acceleration
The acceleration of the bicycle and rider is -1.5 m/s²
Force
The magnitude of the average force needed to bring the bicycle and its rider to a stop is
A person throws a 10kg rock straight up. If the person exerted 3500N of force on the rock over a distance
1 answer:
Answer:
h = 17.83[m]
Explanation:
By means of the working equation which is equal to the product of force by distance, we can find the energy printed at the launch.
where:
W = work [J]
F = force = 3500 [N]
d = distance = 0.5 [m]
Now replacing:
Now, this same work is converted to kinetic energy, necessary for the body to move with an initial velocity. And by energy conservation, we can say that kinetic energy is transformed into potential energy. That is, the kinetic energy will be equal to the potential energy.
where:
Ekin = kinetic energy [J]
Epot = potential energy [J]
Therefore:
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Answer:
The answer is β=0,85 rads
Explanation:
As the ladder is leaning against the building, we can imagine there´s a triangle where 20ft is the hypotenuse and 15ft is the maximum vertical distance between the ladder and the ground, it means, the leg opposite to β which is the angle we need
Let β(betha) be the angle between the ladder and the ground
We also know that
In this case we will need to find β, this way:
Then β=48,6°
We also have that 2πrads is equal to 360°, in this way we find how much β is in radians:
then we find β=0,85rads
Answer:
0.51 m
Explanation:
Using the principle of conservation of energy, change in potential energy equals to the change in kinetic energy of the spring.
Kinetic energy, KE=½kx²
Where k is spring constant and x is the compression of spring
Potential energy, PE=mgh
Where g is acceleration due to gravity, h is height and m is mass
Equating KE=PE
mgh=½kx²
Making x the subject of formula
Substituting 9.81 m/s² for g, 1300 kg for m, 10m for h and 1000000 for k then