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Liula [17]
2 years ago
15

What is the equation for the acid dissociation constant, Ka, of HF?

Chemistry
1 answer:
VashaNatasha [74]2 years ago
4 0

Answer:

hydrofluoric acid HF H+ + F- 7.2 × 10-4

You might be interested in
Both __________ and __________ can be classified as pure substances because they have distinct properties and composition.
musickatia [10]

Answer:

Both <u>elements </u>and <u>compounds</u> can be classifies as pure substances because they have distinct properties and composition.

Explanation:

Elements and compounds are considered as pure substances because both are always formed form are have same kind of atoms.

For example,

Carbon dioxide is compound. It always consist of one carbon atom and two oxygen atoms.

Water is compound it always have same kind of atoms two hydrogen and one oxygen that's why compounds are considered as pure substances.

Same is the case with elements. For example,

Hydrogen is element and it always consist of H atoms.

Iron is another element and it always have iron atoms.

So elements and compounds are always consist of same substances that's why they are considered as pure.

4 0
3 years ago
Select the one that most likely has the highest rate of effusion Oxygen (O2) or hydrogen (H2):
Serhud [2]

The answer is hydrogen (H2) because i just answered this question from Edgenuit.

8 0
3 years ago
What is the molarity (M) of the following solutions?
Dennis_Churaev [7]

Answer:

The molarity (M) of the following solutions are :

A. M = 0.88 M

B. M = 0.76 M

Explanation:

A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.

Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)

                                      = 27 + 3(16 + 1)

                                      = 27 + 3(17) = 27 + 51

                                      = 78 g/mole

Al(OH)_3 = 78 g/mole

Given mass= 19.2 g/mole

Mole = \frac{Given\ mass}{Molar\ mass}

Mole = \frac{19.2}{78}

Moles = 0.246

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Volume = 280 mL = 0.280 L

Molarity = \frac{0.246}{0.280)}

Molarity  = 0.879 M

Molarity  = 0.88 M

B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr​

Molar mass of KBr = 119 g/mole

Given mass = 235.9 g

Mole = \frac{235.9}{119}

Moles = 1.98

Volume = 2.6 L

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Molarity = \frac{1.98}{2.6)}

Molarity = 0.762 M

Molarity = 0.76 M

4 0
2 years ago
a compound with the empirical formula CH2 has a molar mass of 112 g/mol. What is the molecular formula for this compound?
miv72 [106K]
Hope it cleared your doubt :-D

5 0
3 years ago
Metals give up electrons to become cation or anion
galina1969 [7]
Metals usually become cations since electrons are negatively charged and when they are lost there are more protons than electrons making a positive net charge in the atom.  (cations are positively charged ions while anions are negatively charged ions)

I hope this helps.  Let me know if anything is unclear.
8 0
3 years ago
Read 2 more answers
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