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Studentka2010 [4]
2 years ago
7

Throwing a snowball during snowball fight is most like an example of

Chemistry
1 answer:
algol132 years ago
3 0
Ittttt’ssss erosion.
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I NEED HELP ASAP !
Lana71 [14]

Answer:

1.

643.21g  1 mol  6.022^23

262.87 g   1 mol

= 1.4735E24     [Mg3(PO4)2]

2.

4.061x10^24          1mol                22.4 (L)  

6.022^23       1mol

= 151 liters H2O2

3.

479.3g   1 mol   6.022^23

18.02g    1mol

= 1.60E25 H20 atoms

4.

80.34L   1mol       164.1

22.4L       1mol

588.6g   Ca(NO3)2

5.

893.7g   1mol       22.4

44.01g   1mol

= 427 L CO2 or 427.4

6.

5.39 x 10^25     1mol     78.01

6.022^23    1mol

= 6980g Al(OH)3

hope this helps!! :)

8 0
3 years ago
How many grams of Ca(NO3)2 are needed to make 25.0 g of a 15.0% Ca(NO3)2(aq)?
yarga [219]

Answer:

3.75 g.

Explanation:

<em>mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.</em>

<em />

<em>mass % = (mass of solute/mass of solution) x 100.</em>

<em></em>

mass of calcium nitrite = ??? g,

mass of the solution = 25.0 g.

∴ mass % = (mass of solute/mass of solution) x 100

<em></em>

<em>∴ mass of solute (calcium nitrite) = (mass %)(mass of solution)/100</em> = (15.0 %)(25.0 g)/100 = <em>3.75 g.</em>

5 0
3 years ago
How to find the charge of an element
katrin2010 [14]

Answer:

the atomic number is how you find the charge

7 0
3 years ago
"Any process used to ask and answer testable questions about observations of the natural world" defines which term?​
Vlada [557]

Answer:

Scientific inquiry

Explanation:

A scientific inquiry is a systematic way of finding out about certain phenomena in our environment through the use of careful observations and experimentation. It follows a series of steps and procedures which helps a scientist to critically think and observe certain events in his environment. Through the observations, scientific conclusions are then drawn.

7 0
3 years ago
Determine the pH of a 0.461 M C6H5CO2H M solution if the Ka of C6H5CO2H is 6.5 x 10-5. Determine the pH of a 0.461 M C6H5CO2H M
valkas [14]

Answer:

the answer

Explanation:

the answer

3 0
3 years ago
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