Answer:
maximum height on moon is 6 times more than the maximum height on Earth
Explanation:
Let the Astronaut has its maximum speed by which he can jump is "v"
now for the maximum height that it can jump is given as

now from above equation we will have

now we have

now if Astronaut jump on the surface of moon with same speed
then we know that the acceleration of gravity on surface of moon is 1/6 times the gravity on earth
so at surface of moon we have

now we have

so maximum height on moon is 6 times more than the maximum height on Earth
Answer:
The value is 
Explanation:
From the question we are told that
The orbital radius is 
Generally the de Broglie wavelength is mathematically represented as

substituting values


SORRY i forgot but i think its A because the sun has a really strong gravitational pull
sorry and hope it helps
The prefix your looking for is centi as in centimeter. I got this answer on google.
So please mark me as Brainiest.
From Newton's second law of motion, it is identified that the net force applied to the object with mass m, will make it move with an acceleration of a. This can be mathematically translated as,
F = m x a
To solve for the mass of the sled, we derive the equation above such that,
m = F / a
Substituting,
m = (18 N) / (0.39 m/s²)
m = 46.15 kg
Then, we add to the calculated mass the mass of the extra material.
total mass = 46.15kg + 4.5 kg
total mass = 50.65 kg
We solve for the normal force of the surface to the object by calculating its weight.
F₂ = (50.65 kg)(9.8 m/s²)
F₂ = 496.41 N
The force that would allow barely a movement for the object is equal to the product of the normal force and the coefficient of kinetic friction.
F = (F₂)(c)
c = F/F₂
Substituting,
c = 18 N/496.41 N
c = 0.0362
<em>ANSWER: c = 0.0362</em>