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3 years ago

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How many moles of ammonia would be required to react exactly with 0.554 moles of copper(II) oxide in the following in chemical r

eaction? 2 NH3(g) + 3 CuO(s)= 3Cu(s) + N2(g) + 3 H2O(g)

1 answer:

HACTEHA [7]3 years ago

3 0

The mole of ammonia in this chemical equation is 0.36933 moles of NH3... I hope it helped? :)

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3 years ago

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madreJ [45]

Explanation:

The given data is as follows.

Temperature of dry bulb of air = $25^{o}C$

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Partial pressure of water vapor $(P_{a})$ = vapor pressure of water at a given temperature $(P^{s}_{a})$

Using Antoine's equation we get the following.

$ln (P^{s}_{a}) = 16.26205 - \frac{3799.887}{T(K) - 46.854}$

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As total pressure $(P_{t})$ = atmospheric pressure = 760 mm Hg

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The absolute humidity of inlet air = $\frac{P^{s}_{a}}{P_{t} - P^{s}_{a}} \times \frac{18 kg H_{2}O}{29 \text{kg dry air}}$

$\frac{1.18624}{101.325 - 1.18624} \times \frac{18 kg H_{2}O}{29 \text{kg dry air}}$

= 0.00735 kg $H_{2}O$ / kg dry air

Hence, air leaving the humidifier has a has an absolute humidity (%) of 0.07 kg $H_{2}O$ / kg dry air.

Therefore, amount of water evaporated for every 1 kg dry air entering the humidifier is as follows.

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$0.06265 kg \times 100$

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