Answer:
The acid must be a concentrated acid
Explanation:
Ethene is prepared in the laboratory by heating ethanol with excess concentrated tetraoxosulphate VI acid at 170°C . The reactionoccursc in two stages;
1) when the ethanol and sulphuric acid are mixed in a ratio of 1:2, ethyl hydrogentetraoxosulpate VI is formed
2) The compound formed in the first step is heated in the presence of excess concentrated sulphuric acid to give ethene and sulphuric acid.
The overall reaction can be perceived as the dehydration of ethanol. The gas produced (ethene) is usually passed through sodium hydroxide solution to remove any gaseous impurities present.
concentrated sulphuric acid is used in this process since it is a good dehydrating agent.
Jamuuj ExpertThe energy of a wave is directly proportional to the square of the waves amplitude. Therefore, E = A² where A is the amplitude. This therefore means when the amplitude of a wave is doubled the energy will be quadrupled, when the amplitude is tripled the energy increases by a nine fold and so on.Thus, in this case if the energy is 4J, then the amplitude will be √4 = 2 .
<span>First, the child's weight must be converted from pounds to kilograms.
1 lb is equal to 0.453592 kg, so a 13 lb child weighs:
13 lb * 0.453592 kg/lb = 5.896696 kg
Next, use the child's converted weight to determine the mg dosage. The recommended dose is 15 mg per kg, so the recommended dose is:
15 mg/kg * 5.896696 kg = 88.45044 mg
Finally, determine how many mL are needed to provide the calculated mg dosage. One unit of the suspension is 80 mg/0.80 mL. In order to provide 88.45044 mg, you will need
88.45044 mg / 80 mg = 1.1056305 units of the suspension.
Multiplying this by the 0.80 mL portion of the unit of the suspension, you get the final mL dosage:
0.80 mL * 1.1056305 = 0.8845044 mL
A 13 lb child should receive 0.8845044 mL of the 80mg/.8mL suspension.</span>
Answer:
the answer is b,.........
