<span>Answer:
CuX = Cu2+ + X2-
Ksp = [Cu2+] * [X2-]
for each mole of CuX that dissolves we get x mol of each of the anions and cations
Ksp = x^2 = 1.27 x 10 ^-36
x= 1.13 x 10 ^-18 moles of CuX per liter of pure water
if the solution has [Cu2+]= 0.27 M
Ksp becomes x ( x + 0.27)
as we can see above x is extremely small so can be ignored inside the brackets
0.27 x = 1.27 x 10^-36
x = 1.27 x 10^-36 / 0.27 = 4.70 x 10 ^-36 moles per liter
In 0.19M X2- we have
Ksp = 0.19x = 1.27 x 10^-36
x = 1.27 x 10^-36 / 0.19 = 6.68 x 10 ^-36 moles per liter</span>
1) Chemical reaction: HCN + H₂O → CN⁻ + H₃O⁺.
c(HCN) = 2,2 M = 2,2 mol/L.
pKa(HCN) = 9,21.
Ka = 6,16·10⁻¹⁰.
[CN⁻] = [H₃O⁺] = x.
[HCN<span>] = 2,2 M - x.
</span>Ka = [CN⁻] · [H₃O⁺] / [HCN].
6,16·10⁻¹⁰ = x² / 2,2 M -x.
Solve quadratic equation: [CN⁻] = [H₃O⁺] = 0,0000346 M.
[HCN] = 2,2 M - 0,0000346 M = 2,199 M.
2) pH = - log[H₃O⁺].
pH = -log( 0,0000346 M).
pH = 4,46.
Hydrocyanic acid and hydronium ion (H₃O⁺) are acids. Cyanide anion (CN⁻) is the strongest base in the system, cyanide anion accept protons in chemical reaction.
pKb = pKw - pKa.
pKb = 14 - 9,21 = 4,79.
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Answer:
Answer: A. 3 mol 3 mol Al:
Explanation:
Te given balanced chemical equation is :
According to the stochiometry :
A: 3 mol 3 mol Al:
3 moles of chlorine reacts with 2 moles of aluminium
B. 2 mol 3 mol :
2 moles of aluminium reacts with 3 moles of chlorine
C. 2 mol 2 mol Al
2 mol of aluminium produces 2 mol of
D. 3 mol 2 mol
3 moles of chlorine produces with 2 moles of
Thus the conversion factor not used for mole to mole calculations is 3 mol 3 mol Al:
Explanation:
Definitely C, ability to create delicate flavors. :)