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mars1129 [50]
3 years ago
12

Three 15-Ω and two 25-Ω light bulbs and a 24 V battery are connected in a series circuit. What is the current that passes thro

ugh each bulb?
1) 0.18 A
2) 0.25 A
3) 0.51 A
4) 0.74 A
5) The current will be 1.6 A in the 15-Ω bulbs and 0.96 A in the 25-Ω bulbs.
Physics
1 answer:
serious [3.7K]3 years ago
5 0

Answer:

I = 0.25 A

Explanation:

Given that,

Three 15 ohms and two 25 ohms light bulbs and a 24 V battery are connected in a series circuit.

In series combination, the equivalent resistance is given by :

R=R_1+R_2+R_3+....

So,

R=15+15+15+25+25\\\\=95\ \Omega

The current each resistor remains the same in series combination. It can be calculated using Ohm's law i.e.

V = IR

I=\dfrac{V}{R}\\\\I=\dfrac{24}{95}\\\\I=0.25\ A

So, the current of 0.25 A passes through each bulb.

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