3 years ago

Find by means of a vector diagram the resultant of two forces of 7N and 3N acting at right angle to one another

1 answer:

6 0

Answer:

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The resultant of two forces of 7N and 3N acting at a right angle to one another is √58 N. Explanation: Let the magnitude of the force of 7N be denoted as “F₁” on the x-axis and the magnitude of the force of 3N be denoted as “F₂” on the y-axis.Oct 22, 2019

Explanation:

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2 years ago

A particle of mass 10 g and charge 80 mC moves through a uniform magnetic ﬁeld,in a region where the free-fall acceleration is .

Alex777 [14]

Answer:

$B=1.223\frac{T\cdot m}{s}\frac{1}{v}$

Explanation:

According to the first Newton's law, when a particle moves with constant velocity, the sum of forces on it is zero. So, we have:

$F_m=F_g$

Here $F_m=qvBsin\theta$ is the magnetic force and $F_g=mg$ is the gravitational force. The velocity of the particle is perpendicular to the magnetic field, so $\theta=90^\circ$ . Replacing and solving for B:

$qvBsin(90^\circ)=mg\\B=\frac{mg}{qv}\\B=\frac{mg}{q}\frac{1}{v}\\B=\frac{(10*10^{-3}kg)(9.8\frac{m}{s^2})}{80*10^{-3}C}\frac{1}{v}\\B=1.223\frac{T\cdot m}{s}\frac{1}{v}$