Answer:
7.5 moles of O₂.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2KClO₃ —> 2KCl + 3O₂
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 3 moles of O₂.
Finally, we shall determine the number of mole of O₂ produced by the decomposition of 5 moles of KClO₃. This can be obtained as follow:
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 3 moles of O₂.
Therefore, 5 moles of KClO₃ will decompose to produce = (5 × 3)/ 2 = 7.5 moles of O₂.
Thus, 7.5 moles of O₂ were obtained from the reaction.
Answer: 2N2O3 -> 2N2 + 3O2
Explanation:
Answer:
11.2 M → [HCl]
Explanation:
Solution density = Solution mass / Solution volume
35.38 % by mass, is the same to say 35.38 g of solute in 100 g of solution.
Let's determine the moles of our solute, HCl
35.38 g . 1 mol/36.45 g = 0.970 moles
Let's replace the data in solution density formula
1.161 g/mL = 100 g / Solution volume
Solution volume = 100 g / 1.161 g/mL → 86.1 mL
Let's convert the volume to L → 86.1 mL . 1L / 1000 mL = 0.0861 L
Molarity (M) → mol/L = 0.970 mol / 0.0861 L → 11.2 M
