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DENIUS [597]
3 years ago
13

Help me answer this chemistry question. thank you!

Chemistry
1 answer:
Sati [7]3 years ago
8 0

Answer:

A. Inflation pressure of the tyres

Explanation:

In an experiment, the independent variable is the variable that the experimenter changes or manipulates in order to induce a response in another variable called Dependent variable.

In this case in which an experiment was conducted on how inflation pressure of tyre affects a vehicle's maximum speed. The tyres of three different vans were used. The tyre of the first van were set at normal pressure of 35psi, the other van tyres were set at 40psi (overinflated) and 30psi (underinflated) respectively. This means that the INFLATION PRESSURES OF THE TYRES were the variable being changed, hence, is the INDEPENDENT VARIABLE.

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In a titration, 25.0 mL of 0.500 M KHP is titrated to the equivalence point with NaOH. The final solution volume is 53.5 mL. Wha
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M1v1=m2v2 
m2=(m1v1)/v2 
Where m is the molarities and v is the volumes
<span>m2=(25.0*0.500)/53.5
m2=12.5/53.5
m2=0.2336
by rounding off:
m2=0.234 M
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A(n) _____ is the smallest unit of an element that still retains the chemical and physical properties of that element.
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4. How many atom are in <br> C3H5(NO3)3
shepuryov [24]

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How would you prepare 1.00 L of a 0.50 M solution of each of the following?
Lunna [17]

Answer:

Take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water.

Explanation:

Hello,

In this case, for the dilution process from concentrated  12-M hydrochloric acid to 1.00 L of the diluted 0.50M hydrochloric acid, the volume of concentrated HCl you must take is computed by considering that the moles remain constant for all dilution processes as shown below:

n_1=n_2

Which can also be written in terms of concentrations and volumes:

M_1V_1=M_2V_2

Thus, solving for the initial volume or aliquot that must be taken from the 12-M HCl, we obtain:

V_1=\frac{M_2V_2}{M_1} \\\\V_1=\frac{1.00L*0.5M}{12M}\\ \\V_1=0.0417L=41.7mL

It means that you must take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water for such preparation.

Best regards.

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4 years ago
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