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3 years ago

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Which of the following are combustion reactions?

1 answer:

mihalych1998 [28]3 years ago

4 0

Answer:

C₂H₆(g) + O₂(g) ⇒ CO₂(g) + H₂O(l)

Explanation:

Which of the following are combustion reactions?

NaNO₃(aq) ⇒ Na⁺(aq) + NO₃⁻(aq)

NO. This is a dissociation reaction.

C₂H₆(g) + O₂(g) ⇒ CO₂(g) + H₂O(l)

YES. This is a combustion reaction because a compound reacts with oxygen to form carbon dioxide and water.

Mg(s) + HCl (aq) ⇒ H₂(g) + MgCl₂(aq)

NO. This is a single displacement reaction.

HCl(aq) + NaOH (aq) ⇒ HOH(l) + NaCl(s)

NO. This is a neutralization reaction.

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a chemist is studying an unknown substance he can break it into its elemental only by using chemical means.Based on this observa

Vanyuwa [196]

Answer:

Compound

Explanation:

We want to know if it's a compound or a mixture.

An example of a mixture is salt water: you can heat it hot enough to boil off the water, leaving only the salt. This is a physical change, which is how you know it's a mixture.

Something like gold is a compound: if you heat it, or hit it, you'll still only have gold. You can only break it down by chemical means, which is how you know it's a compound.

4 0

3 years ago

The vapor pressure of ethanol at

Karo-lina-s [1.5K]

482VP I think is the correct answer.

5 0

3 years ago

The depletion of ozone (O3) in the stratosphere has been a matter of great concern among scientists in recent years. It is belie

Deffense [45]

<u>Answer:</u> Nitric oxide is the limiting reagent. The number of moles of excess reagent left is 0.0039 moles. The amount of nitrogen dioxide produced will be 0.7912 g.

<u>Explanation:</u>

To calculate the number of moles, we use the equation

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

<u>For ozone:</u>

Given mass of ozone = 0.827 g

Molar mass of ozone = 48 g/mol

Putting values in above equation, we get:

$\text{Moles of ozone}=\frac{0.827g}{48g/mol}=0.0172mol$

<u>For nitric oxide:</u>

Given mass of nitric oxide = 0.635 g

Molar mass of nitric oxide = 30.01 g/mol

Putting values in above equation, we get:

$\text{Moles of nitric oxide}=\frac{0.635g}{30.01g/mol}=0.0211mol$

For the given chemical equation:

$O_3+NO\rightarrow O_2+NO_2$

By Stoichiometry of the reaction:

1 mole of ozone reacts with 1 mole of nitric oxide.

So, 0.0172 moles of ozone will react with = $\frac{1}{1}\times 0.0172=0.0172moles$ of nitric oxide

As, given amount of nitric oxide is more than the required amount. So, it is considered as an excess reagent.

Thus, ozone is considered as a limiting reagent because it limits the formation of product.

Amount of excess reagent (nitric oxide) left = 0.0211 - 0.0172 = 0.0039 moles

By Stoichiometry of the reaction:

1 mole of ozone produces 1 mole of nitrogen dioxide.

So, 0.0172 moles of ozone will react with = $\frac{1}{1}\times 0.0172=0.0172moles$ of nitrogen dioxide

Now, calculating the mass of nitrogen dioxide from equation 1, we get:

Molar mass of nitrogen dioxide = 46 g/mol

Moles of nitrogen dioxide = 0.0172 moles

Putting values in equation 1, we get:

$0.0172mol=\frac{\text{Mass of nitrogen dioxide}}{46g/mol}\\\\\text{Mass of nitrogen dioxide}=0.7912g$

Hence, nitric oxide is the limiting reagent. The number of moles of excess reagent left is 0.0039 moles. The amount of nitrogen dioxide produced will be 0.7912 g.

8 0

4 years ago

386 g ÷ 20cm3 what is density

tatyana61 [14]

22.3 is the answer to this question

3 0

4 years ago

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Which can be classified as a trace fossil

dexar [7]

Trace fossils provide us with indirect evidence of life in the past, such as the footprints, tracks, burrows, borings, and feces left behind by animals, rather than the preserved remains of the body of the actual animal itself. so i would say B.

6 0

3 years ago

Read 2 more answers