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Julli [10]
3 years ago
5

The engineer must place a catch basin at the north west corner of the yard of a subdivision lot. The catchment area will be calc

ulated with a portion of the pervious yard area and the area of the whole impervious roof area.
A. True
B. False
Engineering
1 answer:
castortr0y [4]3 years ago
5 0

Answer:

A = true.

Explanation:

The statement made in the Question or problem above is TRUE/correct. The term known as " catch basin" is an important and essential part of the drainage system that is should be built in a community(whether housing community, industrial community or commercial community).

The catch basin is very important because it helps in making sure that they act as sieve to get all the dirt such as leaves from water running on the surface(runoffs).

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At 45° latitude, the gravitational acceleration as a function of elevation z above sea level is given by g = a − bz , where a =
Ahat [919]

Answer:

8861.75 m approximately 8862 m

Explanation:

We need to remember Newton's 2nd Law which says that the force experienced by an object is proportional to his acceleration and that the constant of proportionality between those two vectors correspond to the mass of the object.

F=ma for the weight of an object (which is a force) we have that the acceleration experienced by that object is equal to the gravitational acceleration, obtaining that  W = mg

For simplicity we work with g =9.807 \frac{m}{s^{2}} despiting the effect of the height above sea level. In this problem, we've been asked by the height above sea level that makes the weight of an object 0.30% more lighter.

In accord with the formula g = a-bz the "normal" or "standard" weight of an object is given by W = mg = ma when z = 0, so we need to find the value of z that makes W = m(a-bz) = 0.997ma meaning that the original weight decrease by a 0.30%, so now we operate...

m(a-bz) = 0.997ma now we group like terms on the same sides ma(1-0.997) = mbz we cancel equal tems on both sides and obtain that z = \frac{a}{b} (0.003) = \frac{9.807 \frac{m}{s^{2} } }{3.32*10^{-6} s^{-2} } (0.003) = 8861.75 m

7 0
3 years ago
For an isotropic material, E and ν are often chosen as the two independent engineering constants. There are other elastic consta
pav-90 [236]

Answer:

khgy

Explanation:

nbv

8 0
3 years ago
5 pts
Softa [21]

Answer:

Helps to accurately calculate job costs

Explanation:

please mark me as brainliest

4 0
3 years ago
In a 5V system if you were asked to take one input HIGH and another LOW what would you do (i.e. where would you connect them)?
dangina [55]

Answer:

HIGH from the supply voltage

LOW from ground

Explanation:

The answer depends on the kind of system and the purpose of the signal. But for practical reasons, in a DIGITAL system where 5V is HIGH and 0 V is LOW, 5 volts can be taken from the supply voltage (usually the same as high,  BUT must be verified), and the LOW signal from ground.

If the user has a multimeter, it must be set to continuous voltage on 0 to 20 V range.  Then place the probe in the ground of the circuit (must be a big copper area). Finally  leave one probe in the circuit ground and place the other probe in some test points to identify 5 v.

4 0
3 years ago
6. After removing the vacuum hose from the fuel-pressure regulator, you see gasoline has dripped out of the hose. Technician A s
lubasha [3.4K]

Answer:

Technician B is correct.

Explanation:

7 0
3 years ago
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