Molarity (M) = moles of solute (mol) / Volume of the solution (L)
Molarity of the solution = 3.000 M
Volume of the solution = 250.0 mL = 0.25 L
moles in 250.0 mL = molarity x volume of the solution
= 3.000 M x 0.25 L
= 0.75 mol
Hence, 0.75 mol of NaCl is needed to prepare 250.0 mL of 3.000 M NaCl solution.
Moles (mol) = mass (g) / molar mass (g/mol)
Moles of NaCl in 250.0 mL = 0.75 mol
Molar mass of NaCl = <span>58.44 g/mol
Mass of NaCl in 250.0 mL = Moles x Molar mass
= 0.75 mol x </span><span>58.44 g/mol
= 43.83 g
Hence, 43.83 g of NaCl is needed to prepare 250.0 mL of 3.000 M solution.</span>
Answer:
the maximum energy available for pumping a mole of glucose into the cell = 3190J
Explanation:
The detailed steps and appropriate derivation from the Vant hoff Isotherm equation is as shown in the attachment.
Answer:
<h3>Right answer is: ( a) chalk powder remains suspended in water.</h3>
Explanation:
Filtration is the technique used to separate suspended solute particles from a solution . The chalk powder remains suspended in the solution and can easily be filtered through a filter paper , the chalk powder can be collected on the filter paper and clear solvent is collected as the filtrate.