Momentum = (mass) x (velocity) = (1,100) x (30) =
33,000
kg-m/sec due east
The octet rule states that atoms tend to form compounds in ways that give them eight valence electrons and thus the electron configuration of a noble gas
Concentration "molarity" of H₂SO₄ in this solution:
5 × 10⁻³ mol / dm³.
<h3>Explanation</h3>
What's the concentration of H⁺ ions in this solution?
![[\text{H}^{+}] = 10^{-\text{pH}}](https://tex.z-dn.net/?f=%5B%5Ctext%7BH%7D%5E%7B%2B%7D%5D%20%3D%2010%5E%7B-%5Ctext%7BpH%7D%7D)
,
where ![[\text{H}^{+}]](https://tex.z-dn.net/?f=%5B%5Ctext%7BH%7D%5E%7B%2B%7D%5D)
is in the unit mol / dm³.
![[\text{H}^{+}] = 10^{-2} \;\text{mol}\cdot\text{dm}^{-3}](https://tex.z-dn.net/?f=%5B%5Ctext%7BH%7D%5E%7B%2B%7D%5D%20%3D%2010%5E%7B-2%7D%20%5C%3B%5Ctext%7Bmol%7D%5Ccdot%5Ctext%7Bdm%7D%5E%7B-3%7D)
.
What's the concentration "molarity" of H₂SO₄ in this solution?
Sulfuric acid H₂SO₄ is a strong acid. Note the subscript "2". Each mole of this acid dissolves in water to produce two moles of H⁺ ions. It takes only 
of H₂SO₄ to produce twice as much H⁺ ions.
As a result, the <em>molarity</em> of H₂SO₄ is 5 × 10⁻³ mol / dm³ or 0.005 M.
Answer: 0.450 M H2SO4
Explanation:
To solve this problem, we must remember how to compute molarity. To find the molarity of a solution, we divide the number of moles by the number of liters of solution. Using this formula and substituting the given values, we get:
Molarity = moles solute/liters solution
= 1.35 moles/3.00 L
= 0.450 M H2SO4
Therefore, the correct answer is 0.450 M H2SO4. Note that the answer has 3 significant figures because each of the given values also contains 3 significant figures.
Hope this helps!
Used the Ideal gas law to get the grams of carbon dioxide
PV=nRT Where p is pressure, v is volume, n is a number of moles, t is temperature and r is the ideal gas constant. The value of R is 0.0821.
Solution
First, find the mole of carbon dioxide
n= PV/RT
= 1 x 1.0 / 0.081 x (2.73 x 102)
= 1 / 0.081 x 278.46
= 1 / 22.56
= 0.045 mol
Convert the moles into grams
Grams of CO2 = 0.045 mol x 44 g/mol = 1.98 g
So the grams of CO2 is 1.98g
