A 0.050 kilogram bullet is fired from a 4.0 kilogram rifle which is initially at
1 answer:
The recoil momentum of the rifle is (3) 20 kg-m/s
Explanation:
We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the bullet-rifle system must be conserved before and after the shot, in absence of external forces.
Before the shot, the total momentum of the system is zero, since both the bullet and the rifle are at rest:
(1)
After the shot, the total momentum of the system is:
(2)
where :
is the momentum of the bullet after the shot
is the recoil momentum of the rifle
Since momentum is conserved, (1) = (2):
Therefore we can find :
where the negative sign tells that the direction is opposite to the momentum of the bullet.
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Answer:
Density of 127 I =
Also,
Explanation:
Given, the radius of a nucleus is given as
.
where,
- A is the mass number of the nucleus.
The density of the nucleus is defined as the mass of the nucleus M per unit volume V.
For the nucleus 127 I,
Mass, M =
Mass number, A = 127.
Therefore, the density of the 127 I nucleus is given by
On comparing with the density of the solid iodine,