A 0.050 kilogram bullet is fired from a 4.0 kilogram rifle which is initially at
1 answer:
The recoil momentum of the rifle is (3) 20 kg-m/s
Explanation:
We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the bullet-rifle system must be conserved before and after the shot, in absence of external forces.
Before the shot, the total momentum of the system is zero, since both the bullet and the rifle are at rest:
(1)
After the shot, the total momentum of the system is:
(2)
where :
is the momentum of the bullet after the shot
is the recoil momentum of the rifle
Since momentum is conserved, (1) = (2):
Therefore we can find :
where the negative sign tells that the direction is opposite to the momentum of the bullet.
Learn more about momentum:
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Answer:
Choices A, B, and C are correct.
Explanation:
Let us look at each of the choices one by one:
A. It is a vector
Yes. Velocity is a vector, or it's a speed with direction.
B. It is the change in displacement divided by the change in time.
Yes. The velocity can be written as
where is the displacement—a vector quantity.
C. It can be measured in meters per second.
Yes. The units of velocity are m/s, but also with a unit vector indicating the direction.
D. It is the slope of the acceleration vs. time graph.
Nope. The velocity is the slope of displacement vs. time graph.
Hence, only choices A, B, and C are correct.
Answer:
26.466cm³/min
Explanation:
Given:
Volume 'V'= 320cm³
P= 95kPa
dP/dt = -11 kPa/minute
pressure P and volume V are related by the equation
P=C
we need to find dV/dt, so we will differentiate the above equation
lets solve for dV/dt, we will have
(plugged in all the values at the instant)
= 26.466
Therefore, the volume increasing at the rate of 26.466cm³/min at this instant