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klasskru [66]
3 years ago
10

5. Alex worked out for 4 hours and lost 3 lbs. during that time. What is the range of water that he should drink in ounces after

his workout?

Physics
1 answer:
Naddika [18.5K]3 years ago
8 0

9 ounces bc if he does then he wont be so like ugh I'm out of wonder land yeah 9 ounces deffo

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<span>
the horizontal velocity would be equal to
Vh = sin (40) /60
= 0.74 * 60
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the Vertical velocity would be equal to
<span>Vv = cos(40) * 60
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The natural enzyme reaction in food slowly breaks it down and eventually causes it to spoil. what 2 things halt this enzyme reac
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At which life cycle stage are stars most stable
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Three children are riding on the edge of a merry‑go‑round that has a mass of 105 kg105 kg and a radius of 1.80 m1.80 m . The mer
rewona [7]

Answer:

New angular speed changes from 16 rpm to 19.95 rpm

Explanation:

In the given system the angular momentum of the system is conserved

initial angular momentum of the system

L_{i}=I_{1}\omega _{1}\\\\\omega _{1}=\frac{8\pi }{15}rad/sec\\\\I_{1}=\frac{1}{2}mr^{2}+(m_{1}+m_{2}+m_{3})r^{2}\\\\I_{1}=\frac{1}{2}\times 105\times 1.8^{2}+(33+28+28) \times 1.8^{2}=458.46kgm^{2}\\\\\therefore L_{i}=458.46\times \frac{8\pi }{15}=768.16

When 28 kg child moves to the center the moment of inertia changes thus we have

I_{2}=\frac{1}{2}mr^{2}+(m_{1}+m_{2})r^{2}\\\\I_{1}=\frac{1}{2}\times 105\times 1.8^{2}+(33+28) \times 1.8^{2}=367.74kgm^{2}\\\\\therefore L_{f}=367.74\times \omega _{f}

Equating initial and final angular momentum we get

I_{2}=\frac{1}{2}mr^{2}+(m_{1}+m_{2})r^{2}\\\\I_{1}=\frac{1}{2}\times 105\times 1.8^{2}+(33+28) \times 1.8^{2}=367.74kgm^{2}\\\\\therefore L_{f}=367.74\times \omega _{f}\\\\\omega _{f}=\frac{768.16}{367.74}=2.1rad/sec\\\\N_{2}=19.95rpm

7 0
3 years ago
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