Answer:
1.048 W
Explanation: Given that a lightbulb has an efficiency of 13.1%.How much light energy (not heat energy) is generated by the bulb every second if the bulb has a power pf 8W?
The input power = 8W
The output power = ?
The efficiency = 13.1%
Using the formula below:
Efficiency = (power output / power input) × 100
13.1 = (Power output / 8 ) × 100
0.131 = power output / 8
Cross multiply to make the power output the subject of formula
Power output = 0.131 × 8
Power output = 1.048 W
Therefore, the light energy (not heat energy) generated by the bulb every second is 1.048 W
♥ 13%=0.13
14400-0.13
Solve: 14399.87
Answer: <span>14399.87</span>
Answer:
Explanation:
Comment
It's actually a deceleration. You should get a negative answer because the ball is slowing down.
Givens
vi = 8.09 m/s
vf = 5.87 m/s
t = 9.17
Formula
a = (vf - vi) /t Substitute the givens into the formula
Solution
a = (5.87 - 8.09)/9.17
Answer
a = - 2.22 m/s^2
