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A stiff wire 44.0 cm long is bent at a right angle in the middle. One section lies along the z axis and the other is along the l

Helga [31]

The magnitude of force acting on wire will be 1.90 N and the direction of the force acting on the wire will be 41.9 degrees below the negative y axis.

Explanation:

It is known that the force acting on a current carrying conductor placed in a magnetic field is

$F=BIL sin theta$

Here B is the magnetic field, I is the current flowing through the wire and L is the length of the wire which is given as 44 cm.

Since the wire is bended in the middle at right angle so the length of the two sides of the wire will be 22 cm each. Also one part is lying over z axis and another part lies in the plane of xy in the equation of line y = 2x. So the slope of this wire will be

$\frac{y}{x} =2$

This will be equal to tan θ.

So θ = tan⁻¹ (2) =63.4°

Then, the length of the wire will be written as components of i, j and k.

$L = (-22)k+(22) cos ( 63.4) i+(22) sin (63.4)j$

$L = 0.098 i+0.197 j-0.22k$

Then,

F = I (L × B)

$F = 20.5 ((0.0985 i + 0.197 j -0.22k) * (0.316 i))$

$F = 20.5 (\left[\begin{array}{ccc}i&j&k\\0.098&0.197&-0.22\\0.316&0&0\end{array}\right] )$

$F = 20.5(i(0)-j(0-(-0.22*0.316))+k(0-(0.316*0.197))) = 20.5(-0.069 j-0.062 k)$

$F = -1.415 j-1.271 k$

The magnitude of force on the wire will be

$F = \sqrt{(-1.415)^{2}+(-1.27)^{2} } = \sqrt{3.615}=1.90 N$

And the direction can be found by the tan inverse of the ratio of k component to j component of the force.

$theta = tan-1(\frac{-1.271}{-1.415})= 41.9 degrees$

So the magnitude of force acting on wire will be 1.90 N and the direction of the force acting on the wire will be 41.9 degrees below the negative y axis.

5 0

4 years ago

(a) A 70-kg person at rest has an oxygen consumption rate Qhum = 14.5 liter/h, 2% of which is supplied by diffusion through the

nevsk [136]

Answer:

(a) $fd=1.7058\times 10^{-5}\ L.hr^{-1}.cm(b) [tex]r=26.008\ cm$

Explanation:

(a)

Oxygen consumption rate of humans, $Q_h=14.5\ L.hr^{-1}$

area of human skin, $A_h=1.7\ m^2$

diffusion rate through skin of humans, $d=2\%\ of\ Q_h$

∴ $d=\frac{2}{100} \times 14.5$

$d=0.29\ L.hr^{-1}$

<u>Flux of diffusion rate, </u>

$fd=\frac{d}{A}$

$fd=\frac{0.29}{17000}$

$fd=1.7058\times 10^{-5}\ L.hr^{-1}.cm(b)Surface area for a spherical animal:[tex]A=4.\pi.r^2$

Diffusion flux rate for animal:

$fd=\frac{14.5}{A}$

$1.7058\times 10^{-5}=\frac{14.5}{4.\pi.r^2}$

$r=26.008\ cm$

4 0

4 years ago

What happens to the brightness of bulb a when the switch is closed and bulb b lights up?

eimsori [14]

The problem describes the relationship of "bulb a" and "bulb b" to be in connected in series. When the switch is open then no current can flow, on the other hand, when it is closed, current will pass through.

When only "bulb a" is connected to the battery then more current is flowing to "bulb a" causing it to be bright.

Closing the switch would mean that "bulb b" is already included in the circuit and the battery will push small current to flow around the whole circuit. The more bulbs are connected, the harder for the current to flow because the resistance will be very high.

So the light of "bulb a" will be dimmer.

8 0

4 years ago

An object with high momentum ______.

Pepsi [2]

The answer should be (b)

7 0

3 years ago

As a 5.0 x 102 N basketball player jumps from the floor up toward the basket, the magnitude of the force of her feet on the floo

s2008m [1.1K]

Here is your answer:

First find the notations:

5.0×10^2=500.
1.0×10^3=1,000

Then you multiply:

1,000×500=500,000

Your answer is...
=500,000 or 5.0×10^4

8 0

4 years ago

Give me more thank plz​

Give me more thank plz