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aniked [119]
3 years ago
6

Give me more thank plz​

Physics
1 answer:
spayn [35]3 years ago
8 0
Ok bro you are going to have 1 more
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I will fan and give 2 medals!!!!!!
Maksim231197 [3]
<span> Corona </span>

<span>I.                  </span>Rare gaseous envelope

<span>II.              </span>Irregular pearly glow

<span>III.          </span>Total solar eclipse

<span>IV.             </span>Surrounds darkened moon

<span>V.                 </span>Caused by diffraction

<span> Solar Prominence </span>

<span>I.                  </span>loop shape

<span>II.              </span>large bright gaseous

<span>III.          </span>luminous hydrogen gas

<span>IV.             </span>rises above chromospheres

<span>V.                 </span>anchored to surface (sun’s surface)

<span> Solar Flare </span>

<span>I.                  </span>Intense High-energy

<span>II.              </span>Causes electromagnetic disruptions

<span>III.          </span>In solar atmosphere

<span>IV.             </span>Varies in brightness

<span>V.                 </span>Emits radiation 

<span> Sunspots </span>

<span>I.                  </span>Surface dark spots

<span>II.              </span>Strong magnetic fields

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<span>IV.             </span> Visible through telescope 

<span>V.                 </span>Cooler than photospheres

I did this in class I got 100%

7 0
3 years ago
I NEED HELP!!! PLS HELP ME MARK U BRAINLIEST!!
FinnZ [79.3K]

Answer:

The answer is X

Explanation:

Cause the highest points will most likely have the most potential energy

8 0
3 years ago
A sealed container holding 0.0255 L of an ideal gas at 0.981 atm and 65 ∘ C is placed into a refrigerator and cooled to 41 ∘ C w
user100 [1]

Answer:

0.911 atm

Explanation:

In this problem, there is no change in volume of the gas, since the container is sealed.

Therefore, we can apply Gay-Lussac's law, which states that:

"For a fixed mass of an ideal gas kept at constant volume, the pressure of the gas is proportional to its absolute temperature"

Mathematically:

p\propto T

where

p is the gas pressure

T is the absolute temperature

For a gas undergoing a transformation, the law can be rewritten as:

\frac{p_1}{T_1}=\frac{p_2}{T_2}

where in this problem:

p_1=0.981 atm is the initial pressure of the gas

T_1=65^{\circ}+273=338 K is the initial absolute temperature of the gas

T_2=41^{\circ}+273=314 K is the final temperature of the gas

Solving for p2, we find the final pressure of the gas:

p_2=\frac{p_1 T_2}{T_1}=\frac{(0.981)(314)}{338}=0.911 atm

3 0
4 years ago
I really need help on this question!​
steposvetlana [31]

Answer:

option "c"

Explanation:

because in gases molecules are further apart and move very quickly

4 0
3 years ago
List five situations in which temporary wiring would be used
Nimfa-mama [501]

an emergency

building a test circuit

temp joining components

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