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3241004551 [841]
3 years ago
15

Tim is pushing a box with a 7 N force. The weight of the box is 5 N. A frictional force

Physics
1 answer:
Vesnalui [34]3 years ago
5 0

Friction and the applied force are not balanced. The 7 N push is countered by the frictional force of 3 N to push the box with a net force of 4 N.

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How do you rearrange the terms in the equation for kinetic energy to solve for velocity?
Andreas93 [3]

Answer:

KE ÷ (1/2 x m) = V²                Which can be rewritten as       V² = KE ÷ (1/2 x m)

Explanation:

To make V² the subject we have to get rid of everything other than V² on the right side of the equation. To do this we use simple algbra rules (it is recommended to get familar with algbra in physics).

Since 0.5 (1/2) is times-ed by mass we can undo this by dividing (since divided by is opposide of times and removes it from the right side.

Now on the left side you have KE ÷ (0.5 x m) = V² remember to use brackets pretty much everytime you do an equation in physics that has more than one operation since it's safer.

And finally remember to square root the answer you get since that will be V².

If this isn't very clear (I'm not very good at explaining alebra) I recommend learning more about it since you will have to use algbra in physics a lot. Some scientific calculators also some with solver which can figure out unknowns for you.

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How does wind power generate electricity?
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I think the answer is A!
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You are standing at the midpoint between two speakers, a distance D away from each. The speakers are playing the exact same soun
Rzqust [24]

Answer:

Explanation:

wave length of sound waves = velocity / frequency

= 340 / 170

λ = 2 m.

When the position of man is exactly at the meddle point between the speakers , sound waves from the speakers reaching man are in same phases ( path difference is zero. ) so intensity of sound is maximum .

Now , the man starts moving towards one of the speakers , his distance from one speaker becomes closer than the other creating path difference for the sound waves reaching his ears.

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When he walks a distance of 1 m , path difference created = 2m

path difference =  λ

so there is constructive interference and maximum  sound will be heard there.

Again we he walks a distance of 1.5 m , path difference created = 3 m

path difference = 3 λ /2

So there will be destructive interference so minimum sound will be heard there.

In this way we see that man starts  from a point of maximum sound intensity , reaches a point of minimum sound intensity , then reaches a point of maximum sound intensity . At last he reaches a position of minimum sound intensity.

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A submarine travels 25 km/h north for 3.2 hours. What is its displacement?
musickatia [10]

80 km is the correct answer   .


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What is the name given to the portion of the electrocardiogram between two waves?.
olya-2409 [2.1K]

Segment

The space between two waves is known as a segment in an ECG. Beginning at the end of the P wave and ending at the beginning of the QRS complex is the PR segment. Beginning at the end of the QRS wave and ending at the beginning of the T wave is the ST segment.

<h3>What is ECG ?</h3>

An electrocardiogram (ECG) is a quick test that can be used to examine the electrical activity and rhythm of your heart. The electrical signals that your heart beats out each time it beats are picked up by sensors that are affixed to your skin.

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Learn more about ECG here:

brainly.com/question/7172728

#SPJ4

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