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3 years ago

Density of water calculation using a 10 mL graduated cylinder

Chemistry

1 answer:

matrenka [14]3 years ago

8 0

Answer:

Average density of the liquid = 0.992 g/mL

Explanation:

Density = mass/volume

mass of liquid = (mass of liquid + mass of cylinder) - mass of cylinder

Trial 1: mass of liquid = 19.731 - 9.861 = 9.87

volume of liquid = 10 mL

density of liquid = 9.87 g / 10 mL = 0.987 g/mL

Trial 2: mass of liquid = 19.831 - 9.861 = 9.97

volume of liquid = 10 mL

density of liquid = 9.97 g / 10 mL = 0.997 g/mL

Trial 3: mass of liquid = 19.831 - 9.861 = 9.97

volume of liquid = 10 mL

density of liquid = 9.97 g / 10 mL = 0.997 g/mL

Trial 4: mass of liquid = 19.771 - 9.861 = 9.91

volume of liquid = 10 mL

density of liquid = 9.91 g / 10 mL = 0.991 g/mL

Trial 5: mass of liquid = 19.751 - 9.861 = 9.89

volume of liquid = 10 mL

density of liquid = 9.89 g / 10 mL = 0.989 g/mL

Average density = (0.987 + 0.997 + 0.997 + 0.991 + 0.989)/5 = 4.961/5

Average density of the liquid = 0.992 g/mL

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Answer:

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Explanation:

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Harrizon [31]

Answer:

$Increase=98.8ppm$

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Explanation:

Hello,

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3 years ago

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k0ka [10]

8305 grams of HNO3 would be needed to prepare 5.5L of a solution. Details on how to calculate mass is found below.

<h3>How to calculate mass?</h3>

The mass of a substance in a solution can be calculated using the following formula:

Density = mass ÷ volume

According to this question, 5.5L of a HNO3 solution is given.

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Therefore, 8305 grams of HNO3 would be needed to prepare 5.5L of a solution.

Learn more about mass at: brainly.com/question/19694949

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2 years ago