Answer:
R=4Ω
Explanation:
R1 and R3 are parrallel
so we have : R=R1*R2/R1+R2
R=6*3/6+3
R=18/9
R=2Ω
R2 and 2Ω are in series,so we have
R=R2+2
R=2+2
R=4Ω
Answer:
Nuclear Reaction
Explanation:
Technically fusion and fission should be included, but a nuclear reaction includes both fusion and fission, so it must be the answer.
Answer:
a) The total force is 4659.8 N
b) The gauge pressure is 50764 Pa
Explanation:
Given:
Pressure inside = 0
Patm = pressure outside = 1.013x10⁵Pa
Pressure difference = ΔP = 1.013x10⁵ - 0 = 1.013x10⁵Pa
a) The area is equal:
The force is:
b) The gauge pressure at the bottom is equal:
Where:
ρ = density = 1000 kg/m³
h = 17 ft = 5.18 m
Replacing:
The power provided by the machine is 13.24 W.
Answer:
Explanation:
Power is determined as the ratio of work done by the system or on the system to the time interval. As the work done is equal to the product of force acting on the system or by the system with the displacement experienced by the system. The power provided by the machine will be
Power = Work done /Time
As the force is given as 121 N and the displacement is given as 15.1 m in a time interval of 2.3 minutes. The time interval should be changed to seconds for each solving ability.
Time taken = 2.3 * 60 s = 138 s
Power = (121×15.1)/138 = 13.24 W.
So the power provided by the machine is 13.24 W.
Answer:
Explanation:
The speed of the bullet will only be the same if the mass of the bullet is equal to the mass of the gun. This because only their momentum ( product of mass and velocity) is conserved; the momentum before the gun and pullet was fired is equal to the momentum of the recoil of the gun and the momentum of the released bullet. The smallest mass receives the highest speed (the bullet) while the larger mass ( the gun) receives the lowest speed ( speed of recoil).
