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3 years ago

Boost your own ______

Physics

1 answer:

Leni [432]3 years ago

6 0

Answer:

Self-confidence

Explanation:

Boost your own self-confidence by living your life, not watching others live their fake ones!

The other choices do not fit as well as self-confidence does, but it's also a common phrase to say "boost your own self-confidence."

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Why can't we say a measurement tool is accurate?

sashaice [31]

There are various reasons why a measurement tool cannot be accurate. One of them is thermal contraction and expansion varies according to seasons.

<h3>What are Accuracy and Precision?</h3>

There are two ways to assess observational error: accuracy and precision. Precision measures how closely two measurements are to one another, whereas accuracy measures how close a group of measurements is to its actual value. In other words, precision is a measure of statistical variability and a description of random errors.

We can say that a tool can be precise, but it cannot be accurate. There are various reasons behind that, some of them are :

It may not be calibrated properly. If there are no reliable standards to use for calibration, this may occur.
Perhaps it strayed. This is why electronic scales include a tare function—they are terrible in this area.
Perhaps the measurements are not linear. Our calipers might have been quite precise at the 2-inch standard, where they were calibrated, but inaccurate at other dimensions.
Temperature is one environmental component that the instrument might be sensitive to. These effects might be compensated for, but the compensation might not be ideal. This issue affects both dissolved solids meters and picometers.

These are some of the reasons due to which measurement tool cannot be accurate.

To get more information about Accuracy and Precision :

brainly.com/question/15276983

#SPJ1

7 0

2 years ago

If we increase the distance traveled when doing work , and keep all other factors the same, what will happen? (2 points) The amo

Solnce55 [7]

I think the amount of force will decrease and the amount of work will increase

4 0

4 years ago

Read 2 more answers

How does the force of gravity between two bodies change when the distance between them doubles? 1. unable to determine; the mass

Rzqust [24]

6. Drop to one quarter of its original value

7 0

3 years ago

Calculate the inhomogeneity of a 1.5 t magnet

Ludmilka [50]

Need more answer choices

6 0

3 years ago

The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proto

igor_vitrenko [27]

a) The angular velocity of the electron is $4.12\cdot 10^{16} rad/s$

b) The number of revolutions per second is $6.54\cdot 10^{15}$ rev/s

c) The centripetal acceleration of the electron is $8.98\cdot 10^{22} m/s^2$

Explanation:

This is a problem of uniform circular motion: in fact, the electron orbits around the proton in a uniform circular motion.

The angular velocity of an object in uniform circular motion is given by

$\omega = \frac{v}{r}$

where

v is the linear speed

r is the radius of the trajectory

For the electron orbiting around the proton, we have

$v=2.18 \cdot 10^6 m/s$

$r=5.29\cdot 10^{-11} m$

Therefore, the angular velocity is

$\omega=\frac{2.18\cdot 10^6}{5.29\cdot 10^{-11}}=4.12\cdot 10^{16} rad/s$

The period of revolution of the electron is given by

$T=\frac{2\pi}{\omega}$

where

$\omega = 4.12\cdot 10^{16}rad/s$ is the angular velocity

Substituting,

$T=\frac{2\pi}{4.12\cdot 10^{16}}=1.53\cdot 10^{-16}s$

The period is the time the electron takes to make one complete orbit around the proton; therefore, the number of revolutions of the electrons in one second is:

$f=\frac{1}{T}=\frac{1}{1.53\cdot 10^{-16}}=6.54\cdot 10^{15}$ rev/s