All categories

3 years ago

If a car goes along a straight road heading east and speeds up from 45 ft/s to 60. ft/s in 5 sec, calculate the

Physics

2 answers:

Lapatulllka [165]3 years ago

8 0

Answer:

Acceleration = 0.9144 m/s^2

Explanation:

Initial speed = 45 ft/s

Final speed = 60 ft/s

Time = 5 sec

Acceleration = a = (v-u) / t

= 60-45 / 5

= 0.9144 m/s^2

Mama L [17]3 years ago

7 0

change the Ft to meters

You might be interested in

A bullet is fired horizontally at a height of 2 meters at a velocity of 930 m/s. Assume no air resistance. How far did the bulle

USPshnik [31]

Answer:

im pretty sure its a

Explanation:

4 0

3 years ago

Read 2 more answers

Joe drove at the speed of 45 miles per hour for a certain distance. He then drove at the speed of 55 miles per hour for the same

Snowcat [4.5K]

Answer:

$v_{avg} = 49.5 mph$

Explanation:

Let the distance moved by Joe is "d"

so the time taken by him to drove it by speed 45 mph is given as

$t_1 = \frac{d}{v_1}$

$t_1 = \frac{d}{45}$

now the same distance is traveled by him with speed 55 mph

so the time taken by him

$t_2 = \frac{d}{55}$

so total time taken by him for complete distance 2d

$t = t_1 + t_2$

$t = \frac{d}{45} + \frac{d}{55}$

$t = 0.0404 d$

now the average speed is given as

$v_{avg} = \frac{2d}{t}$

$v_{avg} = \frac{2d}{0.0404d}$

$v_{avg} = 49.5 mph$

5 0

3 years ago

Read 2 more answers

Which trail is it? Answer!

Pepsi [2]

Wouldn’t it be 1. resistance is high compared to the voltage and with less resistance, higher current

4 0

3 years ago

Read 2 more answers

Prove the correctness of this equation s=vt + 1/2at

Kaylis [27]

Answer:

The formula is dimensionally correct.

Explanation:

Given

$s = ut + \frac{1}{2}at^2$

Required

Prove its correctness

Write out the dimension of each:

$s = M^0LT^0$ --- displacement

$ut = M^0LT^{-1} * T$ --- velocity * time

$\frac{1}{2}at^2 = M^0LT^{-2} * T^2$ --- acceleration * square of time

The expression becomes:

$s = ut + \frac{1}{2}at^2$

$M^0LT^0 = M^0LT^{-1} * T + M^0LT^{-2} * T^2$

Apply law of indices

$M^0LT^0 = M^0LT^{-1+1} + M^0LT^{-2+2}$

$M^0LT^0 = M^0LT^{0} + M^0LT^{0}$

$M^0LT^0 = M^0LT^{0}$

Both sides of the equation are equal

5 0

3 years ago

Why does a lone pair of electrons occupy more space around a central atom than a bonding pair of electrons?

Inessa [10]

Answer:

The lone pair of electrons occupy more space because the electrostatic force becomes weaker.

Explanation:

When there is a bond pair of electrons in the 2 positively charged the atomic nuclei draw the electron density towards them, thereby reducing the bond diameter.

In the case of the lone pair, only 1 nucleus is present, and the enticing electrostatic force becomes weaker and the intensity of the electrons will be increases. Therefore, the lone pair occupies more space than the pair of bonds.

5 0

3 years ago