Answer:
4 m, 1.71 m and 6.29 m
Explanation:
Let L = 8 m be the distance between the two speakers. Let x be the distance from speaker A of constructive interference. The distance to speaker B from the point of constructive interference is thus x₁ = L - x.
There is constructive interference when the distance x₁ - x = nλ where n = is an integer and λ = wavelength L - x
x₁ - x = nλ
L - x - x = nλ
L - 2x = nλ
x = (L - nλ)/2 = (L - nv/f)/2. where v = speed of wave = 343 m/s and f = frequency = 75 Hz
The distance from A where constructive interference would occur starts from when
n = 0
x₂ = (L - nv/f)/2 = (8 - 0 × 343/75)/2 = (8 - 0)/2 = 8/2 = 4 m
n = 1
x₃ = (L - nv/f)/2 = (8 - 1 × 343/75)/2 = (8 - 4.57)/2 = 3.43/2 = 1.71 m
when n = 2
x₄ = (L - nv/f)/2 = (8 - 2 × 343/75)/2 = (8 - 9.14)/2 = -1.15/2 = -0.57 m
So the value at n = 2 is not included.
The third point occurs at x₅ = L - x₃ where x₃ = 1.71 m is the distance away from point B where constructive interference also occurs. (since it is symmetrical about the point x₂ = 4 m
x₅ = L - x₃ = 8 - 1.71 = 6.29 m
Would would have moved a total distance of 2k, because walking is a slower speed does not change distance
A collision from above such as a meteor and an increase in volcano activity.
Answer:
Explanation:
given,
charge = -5.0 μC
Electric force, F = 11 i^ N
force would a proton experience = ?
we know
we know charge of proton is equal to 1.6 x 10⁻¹⁹ C
using formula
Force experienced by the photon in the same field is equal to
