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3 years ago

If an object is placed 10cm in front of a converging lens that has a focal length of 15cm. What are the properties of the image?

Physics

1 answer:

Contact [7]3 years ago

7 0

Answer:

Enlarged [Size]

Virtual and Erect [Nature]

On the same side of the lens as the object [Position]

Explanation:

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Considering thermal equilibrium in your answer, explain why some materials feel different temperatures.

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Two examples of where you can find permanent magnets are
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3 years ago

A little boy is standing at the edge of a cliff 1000 m high. He throws a ball straight downward at an initial speed of 20 m/s, a

marin [14]

Answer:

The ball will be at 700 m above the ground.

Explanation:

We can use the following kinematic equation

$y(t) = \ y_0 \ + \ v_0 \ t \ + \frac{1}{2} \ a \ t^2$ .

where y(t) represent the height from the ground. For our problem, the initial height will be:

$y_0 \ = \ 1000 m$ .

The initial velocity:

$v_0 = - 20 \frac{m}{s}$ ,

take into consideration the minus sign, that appears cause the ball its thrown down. The same minus appears for the acceleration:

$a=-10\frac{m}{s}$

So, the equation for our problem its:

$y(t) = \ 1000 m \ - \ 20 \ \frac{m}{s} \ t \ - \frac{1}{2} \ 10 \frac{m}{s^2} \ t^2$ .

Taking t=6 s:

$y(6 \ s) = \ 1000 m \ - \ 20 \ \frac{m}{s} \ * \ 6 \ s \ - \frac{1}{2} \ 10 \frac{m}{s^2} \ * \ (6 s)^2$ .

$y(6 \ s) = \ 1000 m \ - 120 m - \frac{1}{2} \ 10 \frac{m}{s^2} \ * \ 36 s^2$ .

$y(6 \ s) = \ 1000 m \ - 120 m - 180 m$ .

$y(6 \ s) = \ 1000 m \ - 300 m$ .

$y(6 \ s) = \ 700 m$ .

So this its the height of the ball 6 seconds after being thrown.

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3 years ago

Water in a tank which is positioned 5 feet above the ground is _____ potential energy? (answers would be like thermal, electric,

LUCKY_DIMON [66]

Answer:

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Explanation:

The tank is at rest. And energy of any substance at rest is known as potential energy.

Now, in forms of energy, potential energy is a type of mechanical energy.

Thus, the correct option is mechanical Energy.

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