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Margaret [11]
2 years ago
13

This painting represents the milky way galaxy as it might appear from a distance. Identify the indicated features.

Physics
1 answer:
aksik [14]2 years ago
5 0

The indicated features of how the painting represents the milky way galaxy include the following:

  • Spiral arm
  • Bulge
  • Disk

<h3>What is Milky way?</h3>

This is the galaxy which comprises of our solar system and has a milky appearance when it's viewed from the earth.

The painting represented it as a result of the spiral arm and other features which are listed above.

Read more about Milky way here brainly.com/question/13956361

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Find the acceleration of an 800-kg car that has a net force of 4,000 N acting upon it.
kotykmax [81]

Answer:

The acceleration of the car is 5m/s²

Explanation:

Given data

Force F= 4,000N

Mass of car m= 800kg

Acceleration a= ?

Applying the Newton's second law of motion which states that the rate of change of momentum of a body is proportional to the external force and takes place in the direction of the force

F=ma

a= F/m

a= 4000/800

a=5m/s²

3 0
4 years ago
A fish (6 kg) is being yanked vertically upward out of the water and the fishing line breaks. If the line is rated to a maximum
ANEK [815]

Answer:

15.2 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity. The S.I unit of acceleration is m/s²

From the question,

F-W = ma......................... Equation 1

Where F = Tension on the line, W = weight of the fish, m = mass of the fish, a = acceleration of the fish.

But,

W = mg........................ Equation 2

Where g = acceleration due to gravity.

Substitute equation 2 into equation 1

F-mg = ma

make a the subject of the equation

a = (F-mg)/m.................... Equation 3

Given: F = 150 N, m = 6 kg,

Constant: g = 9.8 m/s²

Substitute into equation 2

a = [150-(6×9.8)]/6

a = (150-58.8)/6

a = 91.2/6

a = 15.2 m/s²

Hence the minimum acceleration of the fish = 15.2 m/s²

4 0
3 years ago
3. What type of current is produced by a battery? (1 point
ladessa [460]

Answer:

direct current hope this helped : )

6 0
4 years ago
A 43 kg girl and a 7.1 kg sled are on the frictionless ice of a frozen lake, 12 m apart but connected by a rope of negligible ma
trapecia [35]

Answer:

(a) Girl acceleration =  0.15 m/s², (b) Sled acceleration =  0.93 m/s²

Explanation:

Given:

M1=Mass of girl = 43 Kg

M2= mass of Sled = 7.1 Kg

Force F= 6.6 N

To Find (a) a1 = girl acceleration  (b) a2 = sled acceleration

Solution:

F1 = F2 = F   (Newton's 3rd Law)

F=ma (Newton's 2nd Law)

(a) F = M1a1

⇒a1 = F/M1 = 6.6 N / 43 Kg = 0.15 m/s²

(b) a2 = F / M2 = 6.6 N / 7.1 Kg =  0.93 m/s²

6 0
3 years ago
Rasheed runs a football 10 meters east, turns and runs the football 6 meters west. If his velocity during this run is found to b
muminat

I believe that would be 48 seconds.

5 0
3 years ago
Read 2 more answers
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