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Margaret [11]
2 years ago
13

This painting represents the milky way galaxy as it might appear from a distance. Identify the indicated features.

Physics
1 answer:
aksik [14]2 years ago
5 0

The indicated features of how the painting represents the milky way galaxy include the following:

  • Spiral arm
  • Bulge
  • Disk

<h3>What is Milky way?</h3>

This is the galaxy which comprises of our solar system and has a milky appearance when it's viewed from the earth.

The painting represented it as a result of the spiral arm and other features which are listed above.

Read more about Milky way here brainly.com/question/13956361

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A steel ball bearing is released from a height H and
ArbitrLikvidat [17]

Answer:

ELASTIC collision

kinetic energy is conservate

Explanation:

As the ball bounces to the same height, it can be stated that the impact with the floor is ELASTIC.

As the floor does not move the conservation of the moment

            po = pf

            -mv1 = m v2

- v1 = v2

So the speed with which it descends is equal to the speed with which it rises

Therefore the kinetic energy of the ball before and after the collision is the same

4 0
3 years ago
Carol can be defined as a social drinker because she can easily limit drinking and she chiefly drinks alcohol when she is out wi
satela [25.4K]
True. These are the characteristics of a social drinker.
6 0
4 years ago
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An object with a mass of 9 kg weighs 14.4 N on the Moon. What is the
erma4kov [3.2K]

Answer:

1.6 m/s²

Explanation:

Weight equals mass times acceleration due to gravity.

F = mg

14.4 N = (9 kg) g

g = 1.6 m/s²

7 0
4 years ago
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A fire helicopter carries a 580-kg bucket of water at the end of a 20.0-m long cable. Flying back from a fire at a constant spee
inn [45]

Answer:

F = 41,954 N

Explanation:

given,

mass of bucket = 580 Kg

length of the cable = 20 m

velocity = 40 m/s

angle made = 38.0°

T cos 38° = m g..............(1)

T sin 38^0 = \dfrac{mv^2}{l} + F......(2)

dividing equation (2) by (1)

tan 38^0 = \dfrac{\dfrac{mv^2}{l} + F}{mg}

tan 38^0 = \dfrac{\dfrac{580\times 40^2}{20} + F}{580 \times 9.81}

4445.36 = \dfrac{580\times 40^2}{20} + F

F = -46400 + 4445.36

F = -41,954 N

hence, the force is acting in the opposite direction as assumed.

F = 41,954 N

4 0
3 years ago
Find the change in velocity of a 369 g hockey puck subject to the force shown below.
Elena-2011 [213]

Answer:

The change in velocity is 15.83 [m/s]

Explanation:

Using the Newton's second law we have:

ΣF = m*a

The force in the graph is 185 N, therefore:

185=0.369*a\\Where\\a=acceleration made it by the force [m/s^2]

a=501.35[m/s^2]

Now using the following kinematic equation:

V^{2}=Vi^{2} + 2*a*(x-xi) \\where\\V=final velocity [m/s]\\Vi= initial velocity [m/s] = 0 the hockey disk is in rest when receives the hit.\\ x = Final position [m] = 0.4 m\\xi = initial position [m] = 0.15m\\

Now replacing the values:

V^{2}=0 + 2*501.35*(0.4-0.15)\\ \\V= 15.83[m/s]

3 0
3 years ago
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