Answer:
12m/s²
Explanation:
Two balls with equal masses and speed engage in a head-on elastic collision. Since the balls of equal mass are moving at equal and opposite speeds, the total linear momentum of the system is zero.
Therefore, the second ball experience an acceleration of 12m/s² at the same time.
We really can't tell from the given information.
We don't know HOW MUCH Marv enlarged his cannonballs,
or HOW MUCH faster Seymour's balls became.
If we assume that they both, let's say, DOUBLED something,
then Seymour accomplished more, and the destructive capability
of his balls has increased more.
I say that because the destructive capability of a cannonball is
pretty much just its kinetic energy when it arrives and hits the target.
Now, we all know the equation for kinetic energy.
K.E. = (1/2) (mass) (speed-SQUARED) .
We can see right away that if Marv started shooting balls with
double the mass but at the same speed, then they have double
the kinetic energy of the old ones.
But if Seymour started shooting the same balls with double the SPEED,
then they have (2-SQUARED) as much kinetic energy as they used to.
That's 4 times as much destructive capability as before.
So we can say that when it comes to cannons and their balls and
smashing things to bits and terrorizing your opponents, if making
a bigger mess is better, then more mass is better, but more speed
is better-squared.
Answer:
D . 1.47 x 10⁻² Ω-m
Explanation:
L = length of the cylindrical resistor = 2 m
d = diameter = 0.1 m
A = Area of cross-section of the resistor = (0.25) d² = (0.25) (3.14) (0.1)² = 0.785 x 10⁻² m²
V = battery Voltage = 12 volts
= current flowing through the resistor = 3.2 A
R = resistance of the resistor
Resistance of the resistor is given as
R = 3.75 Ω
= resistivity
Resistance is also given as
= 1.47 x 10⁻² Ω-m
Answer:
The work function is
Explanation:
From the question we are told that
The light energy is
The stopping voltage is
Generally work function is mathematically represented as
Where KE is the kinetic energy of the ejected electron and it is mathematically represented as
Where e is the charge on the electron
So
Thus
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