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3 years ago

A 50.0 mL sample of HCl required 25.81 mL of 0.1250 M KOH for neutralization. What is the molarity of the acid?

Chemistry

1 answer:

topjm [15]3 years ago

8 0

Answer:

0.065M

Explanation:

The reaction expression is given as:

HCl + KOH → KCl + H₂O

Given parameters:

Volume of KOH = 25.81mL = 0.02581L

Molarity of KOH = 0.125M

Volume of HCl = 50mL = 0.05L

Unknown:

Molarity of the acid = ?

Solution:

To find the molarity of the acid, HCl, let us use the mole concept.

First, find the number of moles of the base, KOH;

Number of moles of KOH = molarity of KOH x volume of KOH

Number of moles of KOH = 0.125 x 0.0258 = 0.003225mol

From the balanced reaction equation:

1 mole of KOH reacted with 1 mole of HCl

0.003225mol of KOH will react with 0.003255mole of HCl

Molarity of HCl = $\frac{number of moles of HCl}{Volume of HCl}$

Molarity of HCl = $\frac{0.003255}{0.05}$ = 0.065M

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