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ss7ja [257]
3 years ago
8

Nanotechnology is technology that is about 1 nm to ______ nm in size.

Physics
2 answers:
hammer [34]3 years ago
8 0

Answer:

100

Explanation:

AnnyKZ [126]3 years ago
6 0

Explanation:

Nanotechnology is science, engineering, and technology conducted at the nanoscale, which is about 1 to 100 nanometers.

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Imagine you are on an airplane. Your plane has flown from 30 degrees North to 42 degrees North. How far have you flown?
ycow [4]
The answer to your question is 12 degrees because you subtract 42 degrees minus 30 degrees to get 12 degrees
7 0
3 years ago
How do I do these? My teacher didn’t show us how.
melisa1 [442]

Explanation:

Displacement is simply the change in position.  So in the first part of problem 1, looking at the graph between 0 s and 2 s, the position changes from 0 m to -4 m.  So the displacement is:

Δx =  -4 m − 0 m

Δx = -4 m

Between 2 s and 4 s, the position stays at -4 m.  The displacement is:

Δx = -4 m − (-4 m)

Δx = 0 m

Finally, between 4 s and 6 s, the position goes from -4 m to 6 m.  The displacement is:

Δx = 6 m − (-4 m)

Δx = 10 m

The net displacement is the change in position from 0 s to 6 s:

Δx = 6 m − 0 m

Δx = 6 m

In the second part of problem 1, we have a velocity vs time graph.

Car 1 starts with 0 velocity and ends with a velocity of 6 m/s, so it is accelerating and constantly moving to the right.

Car 2 starts with a velocity of -6 m/s and ends with a velocity of 6 m/s.  It is also accelerating, but first it is moving to the left, comes to a stop at t = 3 s, then moves to the right.

Car 3 starts with a velocity of 2 m/s and ends with a velocity of 2 m/s.  So it is moving constantly to the right, but never speeds up or slows down.

We want to know when two of the cars meet.  Unfortunately, this isn't as easy as looking for where the lines cross on the graph.  We need to calculate their displacements.  We can do this by finding the area under the graph (assuming all the cars start from the same point).

Let's start with Car 2.  Half of the area is below the x-axis, and half is above.  Without doing calculations, we can say the total displacement for this car is 0.  This means it ends back up where it started, and that it never meets either of the other cars, both of which have positive displacements.

So we know Car 1 and Car 3 meet, we just have to find where and when.  For Car 1, the area under the curve is a triangle.  So its displacement is:

Δx = ½ t v(t)

where t is the time and v(t) is the velocity of Car 1 at that time.  Since the line has a slope of 1 and y intercept of 0, we know v(t) = t.  So:

Δx = ½ t²

Now look at Car 3.  The area under the curve is a rectangle.  So its displacement is:

Δx = 2t

When the two cars have the same displacement:

½ t² = 2t

t² = 4t

t² − 4t = 0

t (t − 4) = 0

t = 0, 4

t = 0 refers to the time when both cars are at the starting point, so t = 4 is the answer we're looking for.  Where are the cars at this time?  Simply plug in t = 4 into either of the equations we found:

Δx = 8

So Cars 1 and 3 meet at 4 s and 8 m.

7 0
3 years ago
What force is necessary to accelerate 32kg object by 2 m/s
Oxana [17]

Answer:

i8nnndnsjdjcicicixidocin where dosoldmxbeus sosojsnnd

Explanation:

nzjwiemddsisjxnxn,jisiskxnxjxjxiisnz MN nsjs. snxjsisisis s. xjsisisk

6 0
2 years ago
O ônibus espacial,preso sobre o avião está em movimento ou repouso?
marissa [1.9K]
Movimento es correcto
6 0
3 years ago
What are precautions in a simple pendulum experiment ​
monitta

Explanation:

1. draught

2. Parallax error

3. angle if displacement

4. air resistance or any form of obstruction

6 0
3 years ago
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