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2 years ago

How do intermolecular forces (IF) and internal kinetic energy (KE) compare in gases?

Physics

1 answer:

Colt1911 [192]2 years ago

5 0

Answer:

IF < KE

Explanation:

The kinetic energy of the gas is greater than the intermolecular forces making the molecules have room to move around without disruption. In a lot of gases, there are sometimes no intermolecular forces between all the particles.

Best of Luck!

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Which of the following must be true for “P if and only if Q” to be true?

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3 years ago

An 8-kg mass is in free fall. What is the velocity of the mass after 9 seconds

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The velocity of the mass after 9 second is 88 m/s

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After a long day you go home in your friend's really fancy sports car which has a sun-roof on the top and a spoiler (a little wi

mixas84 [53]

Answer:

B: air pressure inside the car drops suddenly

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2 years ago

One string of a certain musical instrument is 70.0 cm long and has a mass of 8.79 g . It is being played in a room where the spe

Svetach [21]

To solve this problem we will apply the concepts of linear mass density, and the expression of the wavelength with which we can find the frequency of the string. With these values it will be possible to find the voltage value. Later we will apply concepts related to harmonic waves in order to find the fundamental frequency.

The linear mass density is given as,

$\mu = \frac{m}{l}$

$\mu = \frac{8.79*10^{-3}}{70*10^{-2}}$

$\mu = 0.01255kg/m$

The expression for the wavelength of the standing wave for the second overtone is

$\lambda = \frac{2}{3} l$

Replacing we have

$\lambda = \frac{2}{3} (70*10^{-2})$

$\lambda = 0.466m$

The frequency of the sound wave is

$f_s = \frac{v}{\lambda_s}$

$f_s = \frac{344}{0.768}$

$f_s = 448Hz$

Now the velocity of the wave would be

$v = f_s \lambda$

$v = (448)(0.466)$

$v = 208.768m/s$

The expression that relates the velocity of the wave, tension on the string and linear mass density is

$v = \sqrt{\frac{T}{\mu}}$

$v^2 = \frac{T}{\mu}$

$T= \mu v^2$

$T = (0.01255kg/m)(208.768m/s)^2$

$T = 547N$

The tension in the string is 547N

PART B) The relation between the fundamental frequency and the $n^{th}$ harmonic frequency is

$f_n = nf_1$

Overtone is the resonant frequency above the fundamental frequency. The second overtone is the second resonant frequency after the fundamental frequency. Therefore

$n=3$

Then,

$f_3 = 3f_1$

Rearranging to find the fundamental frequency

$f_1 = \frac{f_3}{3}$

$f_1 = \frac{448Hz}{3}$

$f_1 = 149.9Hz$

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2 years ago

Is there ever a situation where an ant will have more momentum than an elephant? Explain why or why not?

Mariulka [41]

Answer:

Yes

Explanation:

The momentum of an object is given by:

$p=mv$

where

m is the mass of the object

v is the velocity of the object

We know that an elephant has a mass much larger than the mass of an ant. However, we see that the momentum of the animal also depends on its velocity.

If the elephant is at rest, its velocity is zero:

v = 0

so its momentum is also zero:

p = 0

And therefore, an ant which is moving (so, non-zero speed) can have more momentum than an elephant, if the elephant is at rest.

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