Question

A soccer ball is kicked with an initial velocity of 35 m/s at an angle of 60 degrees from the horizontal. How far down the field will the ball hit the ground

Answer 1

Answer:

The ball will hit the ground 108.25 m down the field

Explanation:

To determine how far down the field the ball will hit the ground, that is the Range of the ball. From formula to calculate Range in projectile motion,

$R = \frac{u^{2} sin2\theta }{g}$

Where R is the Range

u is the initial velocity

θ is the angle of projection

and g is acceleration due to gravity (Take g = 9.8 m/s²)

From the question,

Initial velocity, u = 35 m/s

Angle, θ = 60°

Putting these values into the equation, we get

$R = \frac{35^{2} ( sin2(60)) }{9.8}$

$R = \frac{1225 \times sin(120)}{9.8}$

$R = \frac{1225 \times 0.8660}{9.8}$

$R = \frac{1060.85}{9.8}$

$R = 108.25 m$

Hence, the ball will hit the ground 108.25 m down the field.