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guajiro [1.7K]
2 years ago
6

Can u help me pls. ​

Chemistry
1 answer:
lakkis [162]2 years ago
8 0

Answer:

its g :)

Explanation:

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CaC12 * 3H20 is correctly named
ki77a [65]

Answer:

calcium chloride deihydrate

4 0
3 years ago
the amount of water on Earth is _______but the form and location of the water _______ as it moves through the hydrologic cycle
Lorico [155]

Hey there!

I can't be sure my answers are the exact words, but it should be something along the lines of...

The amount of water on Earth is constant, but the form and location of the water changes as it moves through the water cycle.

This means that Earth has always had the same amount of water within in, along with it being the same water the whole time. No new water was introduced to our planet. Some of our water is liquid, some is solid, and some is gas. Some is deep in the soil and some is high up in the atmosphere. Some is in rain and some is in snow.

I hope this helps!

6 0
3 years ago
3
atroni [7]

Answer:

(1) atomic numbers

Explanation:

The observed regularities in the properties of the elements on the periodic table are periodic functions of their atomic numbers.

  • Atomic number is the number of protons in an atom.
  • The periodic law states that "the properties of elements are a periodic function of their atomic number".
  • Elements on the periodic table are arranged based on the atomic numbers they contain.
  • The number of positively charged particles in an atom is the atomic number.
6 0
3 years ago
How would u describe the shape of a big drop of water. Thanks everyone for your help
Furkat [3]

Answer:

It is a semi circle with a triangle on top

6 0
3 years ago
If 3.31 moles of argon gas occupies a volume of 100 L what volume does 13.15 moles of argon occupy under the same temperature an
kumpel [21]

Answer:

397 L

Explanation:

Recall the ideal gas law:

\displaystyle PV = nRT

If temperature and pressure stays constant, we can rearrange all constant variables onto one side of the equation:

\displaystyle \frac{P}{RT} = \frac{n}{V}

The left-hand side is simply some constant. Hence, we can write that:

\displaystyle \frac{n_1}{V_1} = \frac{n_2}{V_2}

Substitute in known values:

\displaystyle \frac{(3.31 \text{ mol})}{(100 \text{ L})}  = \frac{(13.15\text{ mol })}{V_2}

Solving for <em>V</em>₂ yields:

\displaystyle V_2 = \frac{(100 \text{ L})(13.15)}{3.31} = 397 \text{ L}

In conclusion, 13.15 moles of argon will occupy 397* L under the same temperature and pressure.

(Assuming 100 L has three significant figures.)

3 0
2 years ago
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