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Bas_tet [7]
3 years ago
14

A player holds two baseballs a height h above the ground. He throws one ball vertically upward at speed v0 and the other vertica

lly downward at the same speed. Obtain expressions for the speed of each ball as it hits the ground and the difference between their times of flight. (Assume the positive direction is upward.) HINT
Physics
1 answer:
Degger [83]3 years ago
6 0

Answer:

a)  v = √(v₀² + 2g h),    b)      Δt = 2 v₀ / g

Explanation:

For this exercise we will use the mathematical expressions, where the directional towards at is considered positive.

The velocity of each ball is

ball 1. thrown upwards vo is positive

        v² = v₀² - 2 g (y-y₀)

in this case the height y is zero and the height i = h

        v = √(v₀² + 2g h)

ball 2 thrown down, in this case vo is negative

         v = √(v₀² + 2g h)

The times to get to the ground

ball 1

         v = v₀ - g t₁

         t₁ = \frac{v_{o}  - v }{ g}

ball 2

         v =  -v₀ - g t₂

         t₂ = -  \frac{v_{o}  + v }{ g}  

From the previous part, we saw that the speeds of the two balls are the same when reaching the ground, so the time difference is

       Δt = t₂ -t₁

       Δt = \frac{1}{g} \ [(v_{o} - v)  - ( - v_{o}  - v) ]

       Δt = 2 v₀ / g

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Which of the following is an instantaneous speed?
Brilliant_brown [7]

Answer:

A: All of the above

Explanation:

The instantaneous speed of an object is simply the current seed of the object at any given time. The SI unit is m/S and it is a vector quantity.

Therefore, according to the given options, they all have SI units that are consistent with distance and time which makes them all an example of instantaneous speed.

5 0
3 years ago
B. the hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration,
balu736 [363]

The hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration, will be s = 9.5 m.

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.

These equations link five kinematic variables:

Displacement (denoted by Δx)

Initial Velocity v0

Final Velocity denoted by v

Time interval (denoted by t)

Constant acceleration (denoted by a)

These equations define motion at either constant velocity or at constant acceleration. Because kinematics equations are only applicable at a constant acceleration or a constant speed, we cannot use them if either of the two is changing.

v = u + at

0 = 9.5 + a (2)

a = - 9.5 /2  m/s^{2}

v^{2} = u^{2} + 2as

0 =  (9.5)^{2} + 2* (- 9.5 /2) * s

-  (9.5)^{2}  = - 9.5 s

s = 9.5 m

To learn more about kinematics here

brainly.com/question/27126557

#SPJ4

3 0
2 years ago
Why does it take the water in a swimming pool some time to heat up during a hot day?
BartSMP [9]
Because the top layer of a pool will be warmer than the bottom layer, that why filtration is important to cycle the water evenly.
5 0
4 years ago
A diverging lens will always produce an image with _______.
Vlad1618 [11]

Answer:

Option C

Explanation:

Diverging lens are negative lens as they have negative focal length. Their

magnification is smaller than one.

They produce virtual image in which the refracted rays extended back in order to meet

Hence, option C is correct

3 0
3 years ago
A 25 kg child is riding on a swing. If the child travels 8.9 m/s at the bottom of their swing, how high into the air is the chil
Setler [38]

Answer:

h = 4.04 m

Explanation:

Given that,

Mass of a child, m = 25 kg

The speed of the child at the bottom of the swing is 8.9 m/s

We need to find the height in the air is the child is able to swing. Let the height is h. Using the conservation of energy such that,

mgh=\dfrac{1}{2}mv^2\\\\h=\dfrac{v^2}{2g}

Put all the values,

h=\dfrac{(8.9)^2}{2\times 9.8}\\\\h=4.04\ m

So, the child is able to go at a height of 4.04 m.

7 0
3 years ago
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