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3 years ago

A device that has the capacity to receive and store electrical energy is a(n) .

Physics

1 answer:

Dmitriy789 [7]3 years ago

7 0

A capacitor is used to receive and store electrical energy.

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A styrofoam container used as a picnic cooler contains a block of ice at 0°C. If 325 g of ice melts in 1 hour, how much heat ene

Sauron [17]

Answer:

30.0625 W

Explanation:

325 g/h x (1h x 1kg)/(3600s x 1000g) x 3,33 x 10^5 J/Kg = 30.0625 J/Kg = 30.0625 W

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3 years ago

As you ride a bicycle on the sidewalk with a speed of

mixer [17]

Answer:

1.2 seconds

Explanation:

distance = ((final speed + initial speed) * time)/2

Here given:

distance: 3.8 meter

initial speed: 6.4 m/s

final speed: 0 m/s

Solving steps:

3.8 = ((0 + 6.4) * time))/2

3.8 = 3.2(time)

time = 3.8/3.2

time = 1.1875 seconds ≈ 1.2 seconds

5 0

1 year ago

which of these best explains why the hydrogen atoms in a water molecule are attracted to CI ions in sodium chloride

matrenka [14]

The oxygen has more electronegativity (3.44), making hydrogen more 'positive'. Hydrogen will be attracted to Cl since it is more 'negative'. Electronegativity(EN) of H is 2.2 whereas Cl has EN of 3.16

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3 years ago

At the Olympics, high-diving competition,a diver from the top board curves her body in order to?

VMariaS [17]

E increase her speed

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2 years ago

A glass plate 2.25 mm thick, with an index of refraction of 1.80, is placed between a point source of light with wavelength 620

-BARSIC- [3]

Answer:

There are 2.71x10⁴ wavelengths between the source and the screen.

Explanation:

The number of wavelengths (N) can be calculated as follows:

$N = \frac{d_{g}}{\lambda_{g}} + \frac{d_{a}}{\lambda_{a}}$

Where:

$d_{g}$ : is the distance in glass = 2.25 mm

$d_{a}$ : is the distance in air = 1.50 cm - 0.225 cm = 1.275 cm

$\lambda_{g}$ : is the wavelength in glass

$\lambda_{a}$ : is the wavelength in air = 620 nm

To find the wavelength in glass we need to use the following equation:

$n_{g}*\lambda_{g} = n_{a}*\lambda_{a}$

Where:

$n_{g}$ : is the refraction index of glass = 1.80

$n_{a}$ : is the refraction index of air = 1

$\lambda_{g} = \frac{\lambda_{a}}{n_{g}} = \frac{620 nm}{1.80} = 344.4 nm$

Hence, the number of wavelengths is:

$N = \frac{d_{g}}{\lambda_{g}} + \frac{d_{a}}{\lambda_{a}}$

$N = \frac{2.25 \cdot 10^{-3} m}{344.4 \cdot 10^{-9} m} + \frac{1.275 \cdot 10^{-2} m}{620 \cdot 10^{-9} m}$

$N = 2.71 \cdot 10^{4}$

Therefore, there are 2.71x10⁴ wavelengths between the source and the screen.

I hope it helps you!

5 0

3 years ago