Answer:
by using the chromatography you can separate different color
Answer:
3.07 × 10⁻⁴
Explanation:
Step 1: Calculate the concentration of H⁺
We will use the definition of pH.
![pH = -log [H^{+} ]\\\[ [H^{+} ] = antilog -pH = antilog -2.37 = 4.27 \times 10^{-3} M](https://tex.z-dn.net/?f=pH%20%3D%20-log%20%5BH%5E%7B%2B%7D%20%5D%5C%5C%5C%5B%20%5BH%5E%7B%2B%7D%20%5D%20%3D%20antilog%20-pH%20%3D%20antilog%20-2.37%20%3D%204.27%20%5Ctimes%2010%5E%7B-3%7D%20M)
Step 2: Calculate the concentration of HY
5.22 × 10⁻³ mol of HY are dissolved in 0.088 L. The concentration of the acid (Ca) is:

Step 3: Calculate the acid dissociation constant (Ka)
We will use the following expression.
![Ka = \frac{[H^{+}]^{2} }{Ca} = \frac{(4.27 \times 10^{-3} )^{2} }{0.0593} = 3.07 \times 10^{-4}](https://tex.z-dn.net/?f=Ka%20%3D%20%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%5E%7B2%7D%20%7D%7BCa%7D%20%3D%20%5Cfrac%7B%284.27%20%5Ctimes%2010%5E%7B-3%7D%20%29%5E%7B2%7D%20%7D%7B0.0593%7D%20%3D%203.07%20%5Ctimes%2010%5E%7B-4%7D)
Answer:
electrons is the answer to your question
Answer:
1. FeSO4+2NaOH→Na2SO4+Fe(OH)2
2. Fe(NO3)3+3NaOH→Fe(OH)3+3NaNO3
3. 382 g NaNO3
Explanation:
1. This is a double displacement reaction so perform exchanges with specimens and balance accordingly.
2. This is a double displacement reaction so perform exchanges with specimens and balance accordingly.
3. Start with 1.5 mol of Fe(NO3)3 then include mole to mole ratio of NaNO3 to Fe(NO3)3 then multiply by molar mass of Fe(NO3)3.
Answer:
acid is corrosive in nature
acid changes blue litmus to red
acid reacts with base to produce salt and water