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3 years ago

Which of the following fields of science has more scientific theories and fewer scientific laws?

Physics

2 answers:

Sindrei [870]3 years ago

5 0

Answer:

Explanation:

Newton's first law of motion.

Newton's second law of motion.

Newton's law of universal gravitation.

Law of conservation of mass.

Law of conservation of energy.

Law of conservation of momentum

Klio2033 [76]3 years ago

4 0

Answer:The answer is A: Biology :)

Explanation:I got it right.

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A grasshopper makes four jumps. The displacement vectors are (1) 31.0 cm, due west; (2) 26.0 cm, 44.0 ° south of west; (3) 22.0

levacccp [35]

Answer:

(a) 34.47 cm

(b) $24.09^\circ$ south of west

Explanation:

Let us draw a figure representing the individual displacement vectors in the four jumps as shown in the figure attached with this solution.

Now, let us try to write the four displacement vectors in in terms of unit vectors along the horizontal and the vertical axis.

$\vec{d}_1= 31\ cm\ west = -31\ cm\ \hat{i}\\\vec{d}_2= 26\ cm\ south\ of\ west = -26\cos 44^\circ\ \hat{i} -26 \sin 44^\circ\ \hat{j}=(-18.72\ \hat{i}-18.06\ \hat{i})\ cm\\\vec{d}_3= 22\ cm\ south\ of\ east = 22\cos 56^\circ\ \hat{i} -22 \sin 56^\circ\ \hat{j}=(12.30\ \hat{i}-18.23\ \hat{i})\ cm\\\vec{d}_4= 23\ cm\ north\ of\ east = 23\cos 75^\circ\ \hat{i} +23\sin \sin 75^\circ\ \hat{j}=(5.95\ \hat{i}+22.22\ \hat{i})\ cm\\$

Now, the vector sum of all these vector will give the resultant displacement vector.

$\vec{D} = \vec{d}_1+\vec{d}_2+\vec{d}_3+\vec{d}_4\\\Rightarrow \vec{D} = -31\ cm\ \hat{i}+(-18.72\ \hat{i}-18.06\ \hat{i})\ cm+(12.30\ \hat{i}-18.23\ \hat{i})\ cm+(5.95\ \hat{i}+22.22\ \hat{i})\ cm\\\Rightarrow \vec{D} =(-31.47\ \hat{i}-14.07\ \hat{i})\ cm$

Part (a):

The magnitude of the resultant displacement vector is given by:

$D=\sqrt{(-31.47)^2+(-14.07)^2}\ m = 34.47\ m$

Part (b):

Since the resultant displacement vector indicates that the final position of the vector lies in the third quadrant, the vector will make some positive angle in the direction south of west given by:

$\theta = \tan^{-1}(\dfrac{14.07}{31.47})= 24.09^\circ$

4 0

3 years ago

The management information base (MIB) is a repository of data maintained at a managing entity site, providing the network manage

MaRussiya [10]

The management information base (MIB) is a repository of data maintained at a managing entity site, providing the network manager with a centralized, quick-to-query database regarding current network status is considered as false

Explanation:

The management information system is a formal description set of network objects that is managed by using the Simple Network management protocol.

The performance of network is measured based on the delay throughput and packet loss. There are management information system for more related entities that are managed by the companies.

6 0

3 years ago

Calculate the average speed in metres per second from Glasgow to Edinburgh

mariarad [96]

This is the same question as the one previously but with more details, so I will just use my previous answer.

1800 to 1820 is 20 minutes.1830 to 1838 is 8 minutes.1840 to 1905 is 25 minutes.
The total time travelled is 20+8+25 = 53 minutes = 3180 seconds.
The distance between Glasgow and Edinburgh is 28 + 12 + 34 = 74 km = 74000 m.

So, the average speed is 74000m/3180s = 23.27 m/s (4 s.f.)

5 0

3 years ago

Sound Waves....?

Anni [7]

Answer:

longitudinal

Explanation:

because particles of medium through which the sound is transported vibrate parallel to the direction of the sound wave moves

7 0

3 years ago

Read 2 more answers

Water flows at 0.65 m/s through a 3.0 cm diameter hose that terminates in a 0.3 cm diameter nozzle. (Recall, the density of wate

xeze [42]

Answer:

v2 = 65 m/s

the speed of the water leaving the nozzle is 65 m/s

Explanation:

Given;

Water flows at 0.65 m/s through a 3.0 cm diameter hose that terminates in a 0.3 cm diameter nozzle

Initial speed v1 = 0.65 m/s

diameter d1 = 3.0 cm

diameter (nozzle) d2 = 0.3 cm

The volumetric flow rates in both the hose and the nozzle are the same.

V1 = V2 ........1

Volumetric flow rate V = cross sectional area × speed of flow

V = Av

Area = (πd^2)/4

V = v(πd^2)/4 ....2

Substituting equation 2 to 1;

v1(πd1^2)/4 = v2(πd2^2)/4

v1d1^2 = v2d2^2

v2 = (v1d1^2)/d2^2

Substituting the given values;

v2 = (0.65 × 3^2)/0.3^2

v2 = 65 m/s

the speed of the water leaving the nozzle is 65 m/s

6 0

4 years ago