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DaniilM [7]
4 years ago
14

What's going to happen in 3 weeks ?

Physics
2 answers:
PSYCHO15rus [73]4 years ago
8 0

Answer:

the only one who knows is god. god knows.

Explanation:

polet [3.4K]4 years ago
7 0
In reference to what?
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Accorrding to Kepler's third law, a planet whose distance from the Sun is 2 A.U. would have an orbital period of how many Earth-
Lilit [14]

Answer:

hi

Explanation:

4 0
3 years ago
Fluorine (F) has nine protons and ten neutrons. The atomic mass of fluorine is _____.
wel
The atomic mass is roughly equal to the sum of protons and neutrons of an atom. 
9  protons + 10 neutrons = 19
Atomic mass of Flourine is 19. 
8 0
4 years ago
A car of mass 800 kg is travelling at 30 m/S. The car then brakes suddenly and stops with a braking distance of 75 m find the wo
gulaghasi [49]

Answer:

-360 kJ

Explanation:

Given:

m = 800 kg

v₀ = 30 m/s

v = 0 m/s

Δx = 75 m

Find: W

We can solve this using either forces or energy.

To use forces, first find the acceleration.

v² = v₀² + 2aΔx

(0 m/s)² = (30 m/s)² + 2a (75 m)

a = -6 m/s²

Then apply Newton's second law:

∑F = ma

F = (800 kg) (-6 m/s²)

F = -4800 N

Work is force times distance:

W = FΔx

W = (-4800 N) (75 m)

W = -360,000 J

W = -360 kJ

If you want to use energy instead:

work = change in energy

W = ΔKE

W = ½mv² − ½mv₀²

W = ½ (800 kg) (0 m/s)² − ½ (800 kg) (30 m/s)²

W = -360,000 J

W = -360 kJ

4 0
3 years ago
A toy train is pushed forward and released at Xi = 4.0 m with a speed of 2.5 m/s. It rolls at a steady speed for 2.0 s, then one
Fittoniya [83]
I don't think that 4m has anything to do with the problem. anyway. here. A___________________B_______C where A is the point that the train was released. B is where the wheel started to stick C is where it stopped From A to B, v=2.5m/s, it takes 2s to go A to B so t=2 AB= v*t = 2.5 * 2 = 5m The train comes to a stop 7.7 m from the point at which it was released so AC=7.7m then BC= AC-AB = 7.7-5 = 2.7m now consider BC v^2=u^2+2as where u is initial speed, in this case is 2.5m/s v is final speed, train stop at C so final speed=0, so v=0 a is acceleration s is displacement, which is BC=2.7m substitute all the number into equation, we have 0^2 = 2.5^2 + 2*a*2.7 0 = 6.25 + 5.4a a = -6.25/5.4 = -1.157 so acceleration is -1.157m/(s^2)
8 0
3 years ago
Read 2 more answers
An electron with an initial speed of 660,000 m/s is brought to rest by an electric field. What was the initial kinetic energy of
GREYUIT [131]

Answer:

Kinetic energy of the electron E_k=1.23\ eV

Explanation:

It is given that,

Initial speed of an electron, u = 660000 m/s

Final speed of the electron, v = 0 (at rest)

The kinetic energy of an electron is possessed due to the motion of an electron. The mathematical formula for the kinetic energy is given by :

E_k=\dfrac{1}{2}mv^2

m is the mass of electron

E_k=\dfrac{1}{2}\times 9.1\times 10^{-31}\times (660000)^2

E_k=1.98\times 10^{-19}\ J

Since, 1\ eV=1.602\times 10^{-19}\ J

E_k=\dfrac{1.98\times 10^{-19}}{1.602\times 10^{-19}}

E_k=1.23\ eV

So, the initial kinetic energy of the electron is 1.23 eV. Hence, this is the required solution.

7 0
4 years ago
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