<span>We know that the relation between pressure, volume and temperature is constant for ideal gases, so then
P1*V1/T1 = P2*V2/T2
As the volume is held constant, we will have:
P1/T1 = P2/T2
As the pressure is doubled and the temperature in kelvins is 211.15 K, then:
P1/211.15 = 2*P1/T2
T2 = 2*211.15 = 422.3 K
T2 = 422.3 - 273.15 = 149.15
So the final temperature reaches 149.15 ÂşC</span>
We have that for the Question "In the same year, the average finishing <em>time</em> for U.S. women was 4 <u>hours </u>and 41 <em>minutes</em>. What was the average female speed in miles per <em>hour</em>?" it can be said that
The average female speed in miles per hour
![V_a=\frac{D}{4.683hours}](https://tex.z-dn.net/?f=V_a%3D%5Cfrac%7BD%7D%7B4.683hours%7D)
From the question we are told
In the same year, the <u>average</u> finishing <em>time</em> for U.S. women was 4 <u>hours </u>and 41 <em>minutes</em>. What was the average female speed in <u>miles</u> per <em>hour</em>?
<h3>Average speed </h3>
This is defined as the collective <u>mean</u> of different travel <em>intervals </em>
Generally the equation for Speed is mathematically given as
V=\frac{Distance}{Time}
Therefore
For 4 <u>hours </u>and 41 <em>minutes=4.683hours</em>
This travels time was <em>obtained </em>over a series of distance
<em>Hence</em>
<em>Distance D</em>
The average female <em>speed</em> in miles per hour
![V_a=\frac{D}{4.683hours}](https://tex.z-dn.net/?f=V_a%3D%5Cfrac%7BD%7D%7B4.683hours%7D)
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Answer:
Ender's mass = 2.25 kg
Explanation:
using law of conservation of momentum .
since there is inelastic collision
given.
![let \ \ m_{1} = m \\m_{2} = 45 kg \\v_{1} = 12 m/s \\v_{2} = 9 m/s \\\\V_{3} =6.4 m/s\\using \ \ \\m_{1}v_{1} + m_{2}v_{2} = (m_{1} +m_{2})V\\m\times12 + 45\times9 = (m+45)\times6.4\\64m -12m = 405 -288\\52m =117\\m =\frac{117}{52}\\m =2.25kg](https://tex.z-dn.net/?f=let%20%5C%20%5C%20m_%7B1%7D%20%3D%20%20m%20%5C%5Cm_%7B2%7D%20%3D%2045%20kg%20%5C%5Cv_%7B1%7D%20%3D%2012%20m%2Fs%20%5C%5Cv_%7B2%7D%20%3D%209%20m%2Fs%20%5C%5C%5C%5CV_%7B3%7D%20%3D6.4%20m%2Fs%5C%5Cusing%20%5C%20%20%5C%20%5C%5Cm_%7B1%7Dv_%7B1%7D%20%2B%20m_%7B2%7Dv_%7B2%7D%20%3D%20%28m_%7B1%7D%20%2Bm_%7B2%7D%29V%5C%5Cm%5Ctimes12%20%2B%2045%5Ctimes9%20%20%3D%20%28m%2B45%29%5Ctimes6.4%5C%5C64m%20-12m%20%20%20%20%20%20%20%20%3D%20405%20-288%5C%5C52m%20%3D117%5C%5Cm%20%3D%5Cfrac%7B117%7D%7B52%7D%5C%5Cm%20%3D2.25kg)
The correct answer is option ( A) the ratio of their average speeds (bird 1/bird 2) is 1.0
velocity = distance / Time
Let us assume distance covered by Bird 1 = d
case 1 (Bird 1) :-
time = 6 hours
velocity(Bird1) = d/6 = 0.167*d
case 2 (Bird 2) :-
time = 12 hours
distance is twice of Bird 1 = 2d
velocity(Bird2) = 2d/12 = 0.167*d
now, velocity of Bird1/Bird2 = (0.167*d)/(0.167*d) = 1.0
So,velocity of (Bird1/Bird2) is 1.0 .
Average velocity / Average speed = Total displacement / Total distance. Remember that the numerator is less than or equal to the denominator. As a result, the ratio is always equal to or less than one. Distance traveled divided by time taken is the most commonly used formula for calculating average speed. The other formula is to add the initial and final speeds together and divide by two.
Learn more about average speeds here :-
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