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DaniilM [7]
4 years ago
14

What's going to happen in 3 weeks ?

Physics
2 answers:
PSYCHO15rus [73]4 years ago
8 0

Answer:

the only one who knows is god. god knows.

Explanation:

polet [3.4K]4 years ago
7 0
In reference to what?
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A 12.0-g rock is placed in a slingshot with a spring constant of 200 N/m. The rock is stretched back 0.500 m. After the slingsho
kaheart [24]

The maximum velocity of the rock is 64.55 m/s

Answer: Option B

<u>Explanation:</u>

The possessed energy by the objects while motion called kinetic energy. It is directly proportionate to mass and square of velocity. The stored energy in the system called potential energy and expressed as below,

\text { potential energy }=\frac{1}{2} \times(\text { spring constant }) \times\left(\text { distance from equilibrium) }^{2}\right.

                  U=\frac{1}{2} \times k \times x^{2}

U = spring’s potential energy in certain place

k = the spring constant, in N/m.

x = the spring’s distance is stretched or compressed away from equilibrium

Conservation of energy states energy neither created nor destroyed but change from one form to other. So, using this concept, equating both potential and kinetic energies equation we get,

            \frac{1}{2} \times m \times v^{2}=\frac{1}{2} \times k \times x^{2}

Given:

m = 12 g = 0.012 kg

k = 200 N/m

x = 0.500 m

Substitute these values we get,

         \frac{1}{2} \times 0.012 \times v^{2}=\frac{1}{2} \times 200 \times(0.500)^{2}

         v^{2}=\frac{200 \times 0.25}{0.012}=\frac{50}{0.012}=4166.66

Taking square root, we get,

         v=64.55 \mathrm{m} / \mathrm{s}

7 0
3 years ago
The density of solid copper is 8960 kg/m3.
Ahat [919]

Explanation:

The density of a solid copper is 8960kg/m^3 while the density of a molten copper is 7900kg/m^3 this is due to the difference in the state of matter, the solid copper is in solid state while the molten copper is in form of a liquid. In the solid copper atoms are tightly pack while they atom are not tightly packed.

3 0
3 years ago
GIVING BRAINLIEST PLEASE HELP!!
alisha [4.7K]

Answer:

c is the right answer is it

6 0
3 years ago
Question 12 of 15<br> are pictures of relationships.<br> Answer here
Nadya [2.5K]

Answer:

blank

Explanation:

8 0
3 years ago
A spring with a mass of 1 kg has a spring constant 43 kg/s2. If the spring begins at equilibrium position and is given a velocit
Alexxandr [17]

Answer:

Damping constant is equal to 2\sqrt{43}

Explanation:

We have given mass m = 1 kg

Spring constant is given k=43kg/sec^2

For critical damping \zeta =1

We have to find the damping constant

Damping constant is equal to \zeta =\frac{c}{2\sqrt{\frac{k}{m}}}

So 1 =\frac{c}{2\sqrt{\frac{k}{m}}}

c=2\sqrt{\frac{k}{m}}

=2\sqrt{\frac{43}{1}}=2\sqrt{43}

So damping constant is equal to 2\sqrt{43}

5 0
4 years ago
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