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mojhsa [17]
4 years ago
11

What problim in flywheel

Physics
1 answer:
Gwar [14]4 years ago
8 0

Answer:

There are several tell-tale signs that there is a problem with either the starter or flywheel that is preventing your car from starting or causing starting issues. Free spinning is when, for some reason, the starter gear is just spinning without contacting anything. The sound is similar to that of a small drill spinning.

please can u mark me as branliest

hope u liked my answer x

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A 1.98 kg mass is set on a spring, and the spring compression an amount 4.78 cm. what is the spring constant?
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Explain what an exoskeleton is and what it is made of.
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A 14,92kw , 400 v , 400 r.p.m . Dc shunt motor draws a current of 40A when running at full-load. The moment of inertia of the ro
Lostsunrise [7]

First we determine the motor's efficiency - a ratio of the mechanical output power and the electrical input power:

E = \frac{P_out}{P_in}=\frac{14920W}{U\cdot I}=\frac{14920W}{400V\cdot 40A}=0.93

The output mechanical power is directly proportional to torque and angular speed. From this relationship we can isolate the torque:

P_{out}=\tau \cdot\omega=E\cdot P_{in}=E\cdot I \cdot U\\\implies\tau = \frac{I \cdot U \cdot E}{\omega}=\frac{I\cdot U\cdot E\cdot 60}{2\pi\cdot \omega_{rpm}}

whereby the last expression uses the angular speed in rpm units.

(a) we calculate the torque, given that the motor draws 1.2 times the rated current, i.e., 48 Amps:

\tau = \frac{I\cdot U\cdot E\cdot 60}{2\pi\cdot \omega_{rpm}}=\frac{48A\cdot 400V\cdot0.93\cdot 60}{2\pi \cdot 400 rpm} = 426.3 Nm

(b) use formula for the acceleration time:

t_{start} = \frac{j\cdot \omega_{rpm}}{\frac{60}{2\pi}\cdot \tau}=\frac{7.5\frac{kg}{m^2}\cdot 400rpm}{9.55\cdot 426.3kg\frac{m^2}{s^2}}\approx 0.74s

The startup time will be 0.74s

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3 years ago
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