Question

A gas has a pressure of 0.12 atm at 294 K. What is the new pressure at 273 K?​

Answer 1

Answer:

P₂ = 0.11 atm

Explanation:

Given data:

Initial pressure = 0.12 atm

Initial temperature = 294 K

Final pressure = ?

Final temperature = 273 K

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

0.12 atm / 294 K = P₂/273 K

P₂ = 0.12 atm × 273 K / 294 K

P₂ = 32.76 atm. K /294 K

P₂ = 0.11 atm