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vagabundo [1.1K]
3 years ago
13

An element cannot be broken down into other substances by chemical or physical means. But you can still split a sample of an ele

ment into smaller pieces. For example, a piece of aluminum foil can be cut in half and then in half again, and all of the pieces will still be aluminum.What do you think will eventually happen if you could continue dividing that piece of aluminum foil
You will reach the smallest possible piece of the aluminum.
You will divide the aluminum into two smaller elements.
You will continue dividing the aluminum forever into smaller and smaller pieces.
You will reach a point at which there is no matter left.
Chemistry
1 answer:
yaroslaw [1]3 years ago
7 0

Answer:

You will reach the smallest possible piece of the aluminum.

Explanation:

You will not be able to physically separate the aluminum into two smaller elements; aluminum is already a pure elemental substance. It will not divide forever, at some point it will be as small as you can possibly make it. However, you won't be able to erase the matter completely -- it will just become very very small!

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Describe how the freeze-thaw cycle of ice will change the shape of this rock over time. PLSSSS HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!
Ludmilka [50]

Freeze-Thaw Weathering

This action can widen the cracks in the rock, and when the temperature rises above freezing, the ice thaws, allowing the water to seep further into the cracks. As this process of freezing and thawing happens repeatedly, the rock begins to weaken and eventually breaks apart into angular fragments.

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3 years ago
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Compare a heterogeneous mixture and a homogeneous mixture
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3 0
3 years ago
What mass of solid sodium formate (of MW 68.01) must be added to 150 mL of 0.42 mol/L formic acid (HCOOH) to make a buffer solu-
Sergio [31]

Answer:

We need 4.28 grams of sodium formate

Explanation:

<u>Step 1:</u> Data given

MW of sodium formate = 68.01 g/mol

Volume of 0.42 mol/L formic acid = 150 mL = 0.150 L

pH = 3.74

Ka = 0.00018

<u>Step 2:</u> Calculate [base)

3.74 = -log(0.00018) + log [base]/[acid]

0 = log [base]/[acid]

0 = log [base] / 0.42

10^0 = 1 = [base]/0.42 M

[base] = 0.42 M

<u>Step 3:</u> Calculate moles of sodium formate:

Moles sodium formate = molarity * volume

Moles of sodium formate = 0.42 M * 0.150 L = 0.063 moles

<u>Step 4:</u> Calculate mass of sodium formate:

Mass sodium formate = moles sodium formate * Molar mass sodium formate

Mass sodium formate = 0.063 mol * 68.01 g/mol

Mass sodium formate = 4.28 grams

We need 4.28 grams of sodium formate

4 0
3 years ago
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