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Annette [7]
2 years ago
9

Explain why it is important not to correct any gas from the first few seconds of the experiment​

Chemistry
1 answer:
Leno4ka [110]2 years ago
7 0

Answer:

gu kha fuschhehdjdvdbeodbr

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Students find the pH of Substance A to be 2.1 and Substance B to be 4.4. They are told Substance C is less acidic than Substance
Slav-nsk [51]

Answer:

the range should be 2.2 to 4.3

Explanation:

I think so because the numbers at the left side of the scale from 1 are more acidic so as it increases it's still acidic but lesser so 1 is more acidic than 2 so I used 2.2 as the beginning of the range because it's less acidic than A even though its a greater number and 4.3 is lesser than 4.4 but its still greater on the scale. frankly speaking I don't feel so correct because it's in decimal so try and compare facts thank you

8 0
3 years ago
HELP ME PLEASE!!!
777dan777 [17]

Answer:

A bonding that occurs between high electronegative atoms such are N, F, O and H atoms, is called a hydrogen bond. Hydrogen bond is a very strong bond. (C)

If hydrogen bonds are not formed between H atoms and N, F, O atom, then the atoms interact through dispersion forces (also known as london dispersion forces). Dispersion forces are weak and they are temporary forces formed by overlapping of orbitals. (B)

8 0
2 years ago
Read the article. Use your understanding to answer the questions that follow. What type of source is this article? primary or se
valkas [14]

Answer: option C

Explanation:

3 0
3 years ago
Read 2 more answers
How many valence electrons does an atom of rubidium (Rb atomic number 37) have? A.One B.Five C.Six D.37
nadezda [96]
Electronic configuration of Rb: 2.8.8.8.8.3
Valence electron is 3....
4 0
3 years ago
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47.0ml of a HBr solution were titrated with 37.5ml of a 0.215M LiOH solution to reach the equivalence point. what is the molarit
faltersainse [42]

Hello!

The molarity of the HBr solution is 0,172 M.

Why?

The neutralization reaction between LiOH and HBr is the following:

HBr(aq) + LiOH(aq) → LiBr(aq) + H₂O(l)

To solve this exercise, we are going to apply the common titration equation:

M1*V1=M2*V2

M1=\frac{M2*V2}{V1}= \frac{0,215 M * 37,5 mL}{47 mL}=0,172 M

Have a nice day!

4 0
3 years ago
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