Answer:
Cesium fluoride(CsF)
Explanation:
A binary compound is a compound that is composed of 2 distinct element. An ionic compound is composed of ions, usually one is a metal why the other is a non metal. One element gives out electron to form cation and the other receives electron to form anion in a binary compound.
Cesium is a group 1 element and it has one valence electron and it can easily donate this 1 electron to form a bond with other element. Group 1 element are generally very reactive. Cesium is a metal
Fluorine is in group 7 of the periodic table and is a non metal .Fluorine have 7 valency electron and requires 1 electron to form a stable octet.
When cesium and fluorine bond to form a binary compound cesium donate 1 electron and fluorine receives the 1 electron for both element to form a stable octet. The formula for the binary ionic compound of cesium and fluorine can therefore be expressed as Cesium fluoride(CsF)
Morphine sulfate given intravenously, by itself, at once, is known as push.
<h3>What is Morphine ?</h3>
A member of the opiate family of painkillers, morphine is naturally present in opium, a dark-brown substance found in poppies (Papaver somniferum). Morphine can be given orally, sublingually, inhaled, injected into a muscle, injected under the skin, intravenously, into the area around the spinal cord, transdermally, or as a rectal suppository. It causes analgesia and modifies perception and emotional reaction to pain by acting directly on the central nervous system (CNS). With repeated use, tolerance and reliance could develop on both a physical and psychological level. It is widely used for pain from myocardial infarction, kidney stones, and labor pain and can be taken for both acute and chronic pain.
To learn more about Morphine from the given link:
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Answer:
the waves have a trough
Explanation:
just took the test on edg.
To find - Identify what kind of ligand (weak or strong), what kind
of wavelength (long or short), what kind of spin (high spin or
low spin) and whether it is paramagnetic or diamagnetic for
the following complexes.
1. [Mn(CN)6]4-
2. [Fe(OH)(H2O)5]2
3. [CrCl4Br2]3-
Step - by - Step Explanation -
1.
[Mn(CN)⁶]⁴⁻ :
Ligand - Strong
Wavelength - Short
Spin - Low spin
Number of unpaired electrons = 1 ∴ paramagnetic.
2.
[Fe(OH)(H₂O)₅]²⁺ :
Ligand - Weak ( both OH⁻ and H₂O )
Wavelength - Long
Spin - High spin
Number of unpaired electrons = 5 ∴ paramagnetic.
3.
[CrCl₄Br₂]³⁻ :
Ligand - Weak ( both Br⁻ and Cl⁻ )
Wavelength - Long
Spin - High spin
Number of unpaired electrons = 3 ∴ paramagnetic.
