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3 years ago

Which of the following would have the greatest force of gravitational attraction?

Physics

1 answer:

Mekhanik [1.2K]3 years ago

8 0

Answer:

two 5kg objects 2 meters apart✨

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If the momentum of a 1000 kg car travelling at 10 m/s was transferred completely to a 20.0 kg traffic barrier, what would the fi

denis-greek [22]

Answer:

d. 500 m/s

Explanation:

Momentum: This is the product of the mass of a body to its velocity, The S.I unit of momentum is kgm/s.

Mathematically, momentum can be expressed as,

M = mv....................... equation 1

Where M = momentum, m = mass, v = velocity

deduced from the question,

Momentum of the car = momentum of the barrier.

MV = mv ............................. Equation 1

Where M = mass of the car, V = velocity of the car, m = mass of the barrier, v = velocity of the barrier.

making v the subject of the equation,

v = MV/m........................ Equation 2

Given: M = 1000 kg, V = 10 m/s, m = 20 kg.

Substitute into equation 2

v = 1000(10)/20

v = 500 m/s.

Hence the speed of the barrier = 500 m/s

The right option is d. 500 m/s

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3 years ago

The brakes on a truck fail as it approaches a car stopped at a red light. Use Newton’s first and second law of motion to explain

PolarNik [594]

newtons first law states that a object in motion will stay in motion unless acted on by an outside force and an object at rest will stay at rest for the same reason. the force of a moving object is equal to its mass times its acceleration.

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3 years ago

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the diameter of the wheels on your car ( including the tires) is 25 inches. you are going to drive 250 miles today. each of your

timofeeve [1]

So the answer is 324.

Explanation
Because I took that test and I got right if u don’t believe me u can brainy it

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2 years ago

A man weighing 490N on earth weighs 81.7N on the moon.His mass on the moon is kg

Ymorist [56]

His mass is 50 kg . . . on the Moon, on the Earth, in the capsule rocketing between them, and on Halley's comet if he ever goes there.

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3 years ago

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A feather is dropped on the moon from the height of 1.4m. The acceleration of gravity on the moon is 1.67ms-1. Determine the tim

Zinaida [17]

1.3s

Explanation:

Given parameters:

Height = 1.4m

Gravity on moon = 1.67ms⁻¹

Unknown:

Time for feather to fall = ?

Solution:

To solve this problem, we are going to use one of the motion equation that relates time, gravity and height.

H = ut + $\frac{1}{2} g t^{2}$

Sine the body was dropped from rest, initial velocity is zero;

H = height

u = initial velocity

t = time

g = acceleration due to gravity

since u = 0;

H = $\frac{1}{2} g t^{2}$

1.4 = $\frac{1}{2}$ x 1.67 x t²

t = 1.3s

learn more:

Gravity brainly.com/question/10934170

#learnwithBrainly

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3 years ago