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Free_Kalibri [48]
2 years ago
12

Why is Rome warmer than New York in January

Physics
1 answer:
saveliy_v [14]2 years ago
5 0

Answer:

The basic answer is sea flows. On the off chance that the air making a trip to New York moves via land, it will be cooler than the air and flows that reach, for instance, San Francisco. Along these lines, Rome is hotter than New York because of flows, topography and air development designs.

Explanation:

Brainliest?

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What is the magnitude of velocity for a 2,000 kg car possessing 3,000 kg(*)m/s of momentum?
Trava [24]

The magnitude of velocity for this car is equal to 1.5 m/s.

<u>Given the following data:</u>

  • Momentum of car = 3,000 kgm/s.
  • Mass of car = 2,000 kg.

To calculate the magnitude of velocity for this car:

<h3>What is momentum?</h3>

In Science, momentum simply means a multiplication of the mass of an object and its velocity.

Mathematically, momentum is giving by the formula;

Momentum = mass \times velocity

Making velocity the subject of formula, we have:

Velocity=\frac{Momentum}{Mass}

Substituting the given parameters into the formula, we have;

Velocity=\frac{3000}{2000}

Velocity = 1.5 m/s.

Read more on momentum here: brainly.com/question/15517471

5 0
2 years ago
View this and help out??
Zina [86]
I would say b as well. I’m sorry if it’s wrong
5 0
2 years ago
What type of pipe wrenches are designed for turning and holding where marring is not objectionable?
galina1969 [7]
The type of pipe wrenches which are designed to turn and hold where marring is not objectionable is known as the chain wrench.<span> It has two serrated which adjust and grip the pipe. </span>
5 0
3 years ago
A 30,000-kg freight car is coasting at 0.850 m/s with negligible friction under a hopper that dumps 110,000 kg of scrap metal in
erica [24]

Explanation:

Given that,

Mass of a freight car, m_1=30,000-kg

Speed of a freight car, u_1=0.85\ m/s

Mass of a scrap metal, m_2=110,000\ kg

(a) Let us assume that the final velocity of the loaded freight car is V. The momentum of the system will remain conserved as follows :

30000\times 0.85=(30000+110000)V\\\\V=\dfrac{30000\times 0.85}{30000+110000}\\\\=0.182\ m/s

So, the final velocity of the loaded freight car is 0.182 m/s.

(b) Lost on kinetic energy = final kinetic energy - initial kinetic energy

\Delta K=\dfrac{1}{2}[(m_1+m_2)V^2-m_1u_1^2)]\\\\=\dfrac{1}{2}\times [(30,000+110,000 )0.182^2-30000(0.85)^2]\\\\=-8518.82\ J

Lost in kinetic energy is 8518.82. Negative sign shows loss.

6 0
2 years ago
If your weight is 120 pounds and your mass is 54 kilograms how would those values change if you were on the moon
BlackZzzverrR [31]
The gravitation acceleration on the moon is different than on Earth. It is 1.6 m/s^2. If you weigh 120 lbs, then you would multiply 120 pounds by the gravitational acceleration on the moon and then divide by the acceleration on Earth.

(120 lbs * 1.6) / 9.8 = 20 pounds.

The mass will always be the same no matter what planet you’re on, so it’s still 54 kg.
4 0
2 years ago
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