Elements in Group 18 form which ion? A. 1 B. +1 C. -1 D. 0

H2(g) + Br2(l) ⇄ 2HBr(g) Kc = 4.8 × 108

elena-14-01-66 [18.8K]

Answer:

1.5 × 10⁻⁹M

Explanation:

1. Equilibrium equation

H₂(g) + Br₂(l) ⇄ 2HBr(g)

2. Equilibrium constant

The liquid substances do not appear in the expression of the equilibrium constant.

$k_c=\dfrac{[HBr(g)]^2}{[H_2]}=4.8\times 10^8M$

3. ICE table.

Write the initial, change, equilibrium table:

Molar concentrations:

H₂(g) + Br₂(l) ⇄ 2HBr(g)

I 0.400 0

C - x +2x

E 0.400 - x 2x

4. Substitute into the expression of the equilibrium constant

$4.8\times 10^8=\dfrac{(2x)^2}{0.400-x}$

5. Solve the quadratic equation

192,000,000 - 480,000,000x = 4x²

x² + 120,000,000x - 48,000,000 = 0

Use the quadratic formula:

$x=\dfrac{-120,000,00\pm\sqrt{(120,000,000)^2-4(1)(-48,000,000}}{2(1)}$

The only valid solution is x = 0.39999999851M

Thus, the final concentration of H₂(g) is 0.400 - 0.39999999851 ≈ 0.00000000149 ≈ 1.5 × 10⁻⁹M

8 0

3 years ago

How many years old are you if you have lived 1 billion seconds 31 years round this answer to 3 sig figs

stich3 [128]

Answer:

age = 63.2 years

Explanation:

Given data

Number of years = 31

number of seconds = 1 billion

Age = ?

Solution

First we convert seconds to minutes

minutes = 1000000000 / 60

minutes = 16666666.667

Now convert minutes to hours

hours = 16666666.667 / 60

hours = 277777.778

Now convert hours to days

days = 277777.778 / 24

days = 11574.074

Now convert days to months

months = 11574.074 / 30

months = 385.802

Now convert months to years

years = 385.803 / 12

years = 32.15

Now add these years with given years

age = 31 + 32.15

age = 63.2 years

5 0

3 years ago

Noin

OLga [1]

Answer:

Gravity is the answer.

5 0

3 years ago

What happens when: sulphuric acid reacts with zinc.

KonstantinChe [14]

Answer:

hope it helps.

Explanation:

Zinc metal dissolves slowly in dilute sulphuric acid to form solutions containing the aquated Zn(II) ion together with hydrogen gas, H2.

3 0

3 years ago

A sample of hydrated copper (II) sulfate (CuSO4•nH2O) is heated to 150°C and produces 103.74 g anhydrous copper (II) sulfate and

wariber [46]

Answer:

5

Explanation:

Firstly, we convert what we have to percentage compositions.

There are two parts in the molecule, the sulphate part and the water part.

The percentage compositions is as follows:

Sulphate- (103.74)/(103.74 + 58.55) × 100% = apprx 64%

The water part = 100 - 64 = 36%

Now, we divide the percentages by the molar masses.

For the CuSO4 molar mass is 64 + 32 + 4(16) = 160g/mol

For the H2O = 2(1) + 16 = 18g/mol

Now we divide the percentages by these masses

Sulphate = 64/160 = 0.4

Water = 36/18 = 2

The ratio is thus 0.4:2 = 1:5

Hence, there are 5 water molecules.

3 0

3 years ago