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ehidna [41]
2 years ago
8

A container with a mass of 5 kg is lifted to a height of 8 m

Physics
1 answer:
Ne4ueva [31]2 years ago
3 0

It takes 392 joules of work to lift it.

It has 392 joules of gravitational potential energy up there.

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If you are traveling around a curve at a constant speed will your velocity change?
marta [7]

Velocity means [ (speed) and (direction) ].

If you're traveling around a curve, then your direction is
always changing.  So your velocity is always changing,
even if your speed isn't.
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3 years ago
elements are organized based on their properties on a chart called modern periodic table which of the following statements is tr
Illusion [34]

Answer:

Elements are arranged in the table by increasing atomic number.

Explanation:

In the modern periodic table, each element is represented by its chemical symbol. The number above each symbol is its atomic number.

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3 years ago
A 25.0-kg test rocket is fired vertically. When the engine stops firing, the rocket’s kinetic energy is 2017 J. After the fuel i
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1. 2.12105 J. The final kinetic energy is. KE f mv2. (875.0 kg)(44.0 m/s)2 2.What is the velocity of the two hockey players after the collision? ... A 10.0-kg test rocket is fired vertically from.

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3 years ago
On earth, what is a child’s mass if the force of gravity on the child’s body is 100 N
ikadub [295]

Answer: 10.2 kg if g = 9.8, 10 if g = 10.

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Weight or the "force of gravity" on a person is simply defined by the equation: F = ma. In this case, the acceleration is g, which is 9.8 but can be rounded up to 10. Based on this, we have:

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4 0
3 years ago
A 6.00-kg box sits on a ramp that is inclined at 37.0° above the horizontal. the coefficient of kinetic friction between the box
forsale [732]
We need to see what forces act on the box:

In the x direction:

Fh-Ff-Gsinα=ma, where Fh is the horizontal force that is pulling the box up the incline, Ff is the force of friction, Gsinα is the horizontal component of the gravitational force, m is mass of the box and a is the acceleration of the box.

In the y direction:

N-Gcosα = 0, where N is the force of the ramp and Gcosα is the vertical component of the gravitational force. 

From N-Gcosα=0 we get: 

N=Gcosα, we will need this for the force of friction.

Now to solve for Fh:

Fh=ma + Ff + Gsinα,

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G=mg, where m is the mass of the box and g=9.81 m/s²

Fh=ma + μmgcosα+mgsinα

Now we plug in the numbers and get:

Fh=6*3.6 + 0.3*6*9.81*0.8 + 6*9.81*0.6 = 21.6 + 14.1 + 35.3 = 71 N

The horizontal force for pulling the body up the ramp needs to be Fh=71 N.
8 0
2 years ago
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