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3 years ago

3. Calculate the force it would take to accelerate a 50 ka bike at a rate of 3 m/s2 (6 points)

Physics

1 answer:

qwelly [4]3 years ago

8 0

Answer:

150 N

Explanation:

Given that,

Acceleration (a) = 3 m/s²
Mass of the bike (m) = 50 kg

We are asked to calculate force required.

$\longrightarrow$ F = ma

$\longrightarrow$ F = (50 × 3) N

$\longrightarrow$ F = 150 N

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A ball is launched with an initial velocity of 3m/s, at an angle of 40 degrees above the horizontal, and from a height of 0.5m.

Brut [27]

Answer:

The ball travels 1.31 m horizontally before hitting the ground.

Explanation:

Given:

Initial velocity of the ball is, $u=3\ m/s$

Angle of projection is, $\theta=40\ degree$

Initial height of the ball is, $y_0=0.5\ m$

Final height of the ball is, $y=0\ m$

Now, horizontal and vertical components of initial velocity are given as:

$u_x=u\cos\theta\\\\u_y=u\sin\theta$

Plug in the given values and find $u_x\ and\ u_y$ . This gives,

$u_x=3\ m/s\times \cos(40)\\\\u_x=2.3\ m/s\\\\u_y=3\ m/s\times \sin(40)\\\\u_y=1.9\ m/s$

Now, there is acceleration due to gravity acting in the vertical direction. The direction is downward. So, $g=-9.8\ m/s^2$ .

Now, using equation of motion in the vertical direction, we have:

$y-y_0=u_yt+\frac{1}{2}a_y t^2$

Plug in the given values and solve for time 't'. This gives,

$0-0.5=1.9t-0.5\times 9.8\times t^2\\\\-0.5=1.9t-4.9t^2\\\\4.9t^2-1.9t-0.5=0$

On solving the above quadratic equation, we get:

$t=0.57\ s\ or\ t=-0.18\ s$

Ignoring the negative result as time can't be negative. So, time taken by the ball to reach the ground is 0.57 s.

Now, as the ball moves, there is no force acting on it in the horizontal direction. So, the acceleration in the horizontal direction is 0.

Now, we know that, when acceleration is zero, the body moves with a constant speed.

Hence, distance traveled in the horizontal direction is given as:

Horizontal distance = Horizontal component of initial velocity × Time

$R=u_x\times t$

Plug in the given values and solve for 'R'. This gives,

$R=2.3\times 0.57\\\\R=1.31\ m$

So, the ball travels 1.31 m horizontally before hitting the ground.

6 0

3 years ago

220V and 5A is supplied to the primary coil. The turns ratio is 500. What is the power on the secondary coil?

alisha [4.7K]

Answer: 1100 W

Explanation:

Input power = 220(5) = 1100 W

The transformer will step up/down voltage, but will also step down/up current.

Neglecting hysteresis and other minor losses, the power will remain the same.

4 0

2 years ago

Which part of a laser printer applies a positive charge to the paper that attracts the toner particles to it

Shalnov [3]

The part of laser printer that applies a positive charge to the paper in order to attract the toner particles is known as transfer roller.

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What is a laser printer:

A laser printer is a kind of printer that uses the electrostatic digital printing process to perform printing. It makes use of the static electricity and toner powder in place of liquid ink.

The toner is applied to specific areas which are dependent on the charge difference created or on the static electricity.

Following are the components of a laser printer:

Scanning unit:

This unit of a laser printer generally consists of a laser diode, a

scanning motor and a polygon mirror.
It also consists of two-beam alignment lenses.

Cartridge unit:

This unit of laser printer consists of three drums, namely primary

charging roller (PCR), organic photoconductive drum (OPC) , and

image transfer roller (ITR).
The transfer roller is also present at a close vicinity of the

printer's toner cartridge.

Fuser assembly unit:

This unit of laser printer consists of a pressure roller and a fuser roller, where the fuser roller assembly consists of a heating

element.

Therefore, the transfer roller unit of a laser printer applies a positive charge to the paper that attracts the toner particles to it.

Learn more about laser printers here:

brainly.com/question/5039703

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6 0

2 years ago

Explain how to correctly add vectors in 2-D

Simora [160]

To add vectors we can use the head to tail method (Figure 1).
Place the tail of one vector at the tip of the other vector.
Draw an arrow from the tail of the first vector to the tip of the second vector. This new vector is the sum of the first two vectors.

8 0

3 years ago

A car engine applies a force of 65,000 N, how much work is done by the engine as it pushed a car a distance of 75 m?

kupik [55]

Answer:

$workdone = force \times distance \\ = 65000 \times 75 \\ = 4,875,000 \: J$

3 0

3 years ago