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Darya [45]
2 years ago
13

3. Calculate the force it would take to accelerate a 50 ka bike at a rate of 3 m/s2 (6 points)

Physics
1 answer:
qwelly [4]2 years ago
8 0

Answer:

150 N

Explanation:

Given that,

  • Acceleration (a) = 3 m/s²
  • Mass of the bike (m) = 50 kg

We are asked to calculate force required.

\longrightarrow F = ma

\longrightarrow F = (50 × 3) N

\longrightarrow <u>F</u><u> </u><u>=</u><u> </u><u>1</u><u>5</u><u>0</u><u> </u><u>N</u>

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Now assume that the frictional force f is not at its maximum value. What is the relation between the torque Ï„ applied to each w
leva [86]

Answer:

a)The direction the frictional force will acts is in the positive x direction.

Explanation:

a)The direction the frictional force will acts is in the positive x direction

b)in the horizontal direction, the total force F(total) is equal to 4times the frictional force in the wheel.

F(total)=4f

''f'' is taken as the frictional force.

c)4times the normal force on each wheel minus the acceleration equals zero i.e 4N(wheel)-a=0

=4N(wheel)-mg=0

d) torque is the force that tends to bend rotation

ζ=rf

but acceleration=4×frictional force

cross multiply

f=ζ/r

f=ma/4

ma/4=ζ/r

a=4ζ/r

5 0
3 years ago
Read 2 more answers
A spherical, non-conducting shell of inner radius = 10 cm and outer radius = 15 cm carries a total charge Q = 13 μC distributed
Vaselesa [24]

Answer:

E = 1580594.95 N/C

Explanation:

To find the electric field inside the the non-conducting shell for r=11.2cm you use the Gauss' law:

\int EdS=\frac{Q_{in}}{\epsilon_o}   (1)

dS: differential of the Gaussian surface

Qin: charge inside the Gaussian surface

εo: dielectric permittivity of vacuum =  8.85 × 10-12 C2/N ∙ m2

The electric field is parallel to the dS vector. In this case you have the surface of a sphere, thus you have:

\int EdS=ES=E(4\pi r^2)   (2)

Qin is calculate by using the charge density:

Q_{in}=V_{in}\rho=\frac{4}{3}(r^3-a^3)\rho  (3)

Vin is the volume of the spherical shell enclosed by the surface. a is the inner radius.

The charge density is given by:

\rho=\frac{Q}{V}=\frac{13*10^{-6}C}{\frac{4}{3}\pi((0.15m)^3-(0.10m)^3)}\\\\\rho=1.30*10^{-3}\frac{C}{m^3}

Next, you use the results of (3), (2) and (1):

E(4\pi r^2)=\frac{4}{3\epsilon_o}(r^3-a^3)\rho\\\\E=\frac{\rho}{3\epsilo_o}(r-\frac{a^3}{r^2})

Finally, you replace the values of all parameters, and for r = 11.2cm = 0.112m you obtain:

E=\frac{1.30*10^{-3}C/m^3}{3(8.85*10^{-12}C^2/Nm^2)}((0.112m)-\frac{(0.10)^3}{(0.112m)^2})\\\\E=1,580,594.95\frac{N}{C}

hence, the electric field is 1580594.95 N/C

7 0
3 years ago
Snakes and lizards are rarely found near polar environment explain why
Novosadov [1.4K]
Reptiles, such as snakes and lizards, are cold-blooded animals. This means that they do not have the ability to control their body heat. For this reason, they often lay out in the sun to warm up. If their enviornent is cold they obtain that body temperature. They are very slow in colder environments.In cold weather these animals have a very difficult time moving because their muscles are very cold. Without heat in their environment, they cannot warm them up.
4 0
3 years ago
What force does it take to accelerate a 9.2 kg object 7.0 m/s^2?
Ulleksa [173]

Answer:

<h2>64.4 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

mass = 9.2 kg

acceleration = 7 m/s²

We have

force = 9.2 × 7 = 64.4

We have the final answer as

<h3>64.4 N</h3>

Hope this helps you

5 0
2 years ago
A small model car with mass m travels at a constant speed on the inside of a track that is a vertical circle radius 5.00 m. If t
dolphi86 [110]
One point to another
6 0
3 years ago
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