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2 years ago

3. Calculate the force it would take to accelerate a 50 ka bike at a rate of 3 m/s2 (6 points)

Physics

1 answer:

qwelly [4]2 years ago

8 0

Answer:

150 N

Explanation:

Given that,

Acceleration (a) = 3 m/s²
Mass of the bike (m) = 50 kg

We are asked to calculate force required.

$\longrightarrow$ F = ma

$\longrightarrow$ F = (50 × 3) N

$\longrightarrow$ F = 150 N

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1. Johnny wants to know where the water line is in a dark well. He drops a penny into the well and counts until he hears the pen

777dan777 [17]

Answer:

3 feet down

Explanation:

i think

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3 years ago

Which statement is true for a car that first goes around a curve of radius r at a constant speed v, and then goes around the sam

sasho [114]

Centripetal force is equal to (mv^2)/r
The way I use to answer these question is to set every variable to 1
m=1
v=1
r=1
so centripetal force =1
then change the variable we're looking at
and since we're find when it's half we could either change it to 1/2 or 2, but 2 is easier to use
m=1
v=2
r=1
((1)×(2)^2)/1=4
So the velocity in the 1st part is half the velocity in the 2nd part and the centripetal force is 4× less
The answer is the centripetal force is 1/4 as big the second time around

3 0

3 years ago

You are performing a knee extension exercise. You hold a 20kg weight at full knee extension. The weight is 0.4m from your knee j

dmitriy555 [2]

Answer:

The moment is -78.4 N-m (clockwise).

Explanation:

Given:

Mass of the object (m) = 20 kg

Distance of the object from the knee joint (d) = 0.4 m

Weight of leg is not considered.

Acceleration due to gravity (g) = 9.8 m/s²

Now, weight of the object is equal to the product of its mass and acceleration due to gravity. So,

Weight = Mass × Acceleration due to gravity

= $mg=20\times 9.8 =196\ N$

We know that, moment of a force about a point is defined as the product of force applied and the perpendicular distance between the point and the line of application of force.

Moment of the given weight about the knee joint is given as:

Moment about knee joint = Weight × Distance from knee joint to weight

Moment about knee joint = 196 × 0.4 = 78.4 Nm

Now, from the diagram below, we can observe that, the weight acts vertically down and thus the sense of rotation about the knee joint at point O is clockwise. So, moment is negative.

Therefore, the moment is -78.4 N-m (clockwise).

7 0

3 years ago

. A 13-g goldfinch has a speed of 8.5 m/s. What is its kinetic energy?

lesya692 [45]

PLEASE PRESS THE “Thanks!” BUTTON! :)
13 g —> 0.013 kg
KE = 1/2(m)(v)^2
KE = 1/2(0.013)(8.5)^2
KE = 0.47 J

3 0

2 years ago

A child is riding a merry-go-round that is turning at 7.18 rpm. If the child is standing 4.65 m from the center of the merry-go-

iVinArrow [24]

Answer:

B) 3.50 m/s

Explanation:

The linear velocity in a circular motion is defined as:

$v=\omega r(1)$

The angular frequency ( $\omega$ ) is defined as 2π times the frequency and r is the radius, that is, the distance from the center of the circular motion.

$\omega=2\pi f(2)$

Replacing (2) in (1):

$v=2\pi fr$

We have to convert the frequency to Hz:

$7.18rpm*\frac{1Hz}{60rpm}=0.12Hz$

Finally, we calculate how fast is the child moving:

$v=2\pi(0.12Hz)(4.65m)\\v=3.5\frac{m}{s}$

3 0

3 years ago