Answer: Mass Of CFC that needs to evaporate for the freezing of water = 328.24 g
Explanation: Heat gained by the CFC = Heat lost by water
Heat lost by water = Heat required to take water's temperature to 0°c + Heat required to freeze water at 0°c
Heat required to take water's temperature from 33°c to 0°c = mCΔT
m = 201g, C = 4.18 J/(gK), ΔT = 33
mCΔT = 201 × 4.18 × 33 = 27725.94 J
Heat required to freeze water at 0°c = mL
m = 201g, L = 334 J/g
mL = 201 × 334 = 67134 J
Heat gained by CFC to vaporize = mH = 27725.94 + 67134 = 94859.94 J
H = 289 J/g, m = ?
m × 289 = 94859.9
m = 328.24 g
QED!!
I think it’s a product... i don’t think it reacts to anything. i could be wrong tho:)
Answer:
4C₈H₄OH + 35O₂ → 32CO₂ + 10H₂O
Explanation:
The unbalanced reaction expression is given as:
C₈H₄OH + O₂ → CO₂ + H₂O
To solve this problem, we use a mathematical approach.
aC₈H₄OH + bO₂ → cCO₂ + dH₂O
Conserving C: 8a = c
H: 5a = 2d
O: a + 2b = 2c + d
Let a = 1, c = 8, d = , b = 35
4C₈H₄OH + 35O₂ → 32CO₂ + 10H₂O
Answer:
The answer to your question is below
Explanation:
Data
[HBr] = 0.045 M
[H⁺] = ?
[OH⁻] = ?
pH = ?
pOH = ?
Process
1.- Determine the [H⁺]
The [H⁺] is equal to the [HBr] then, [H⁺] = 0.045 M
2.- Determine the pH
pH = -log[H⁺]
-Substitution
pH = -log[0.045]
-Result
pH = 1.35
3.- Determine the pOH
Formula
pH + pOH = 14
-Solve for pOH
pOH = 14 - pH
-Substitution
pOH = 14 - 1.35
-Result
pOH = 12.65
4.- Determine the [OH⁻]
pOH = -log[OH⁻]
-Solve for [OH⁻]
[OH⁻] = antilog(-pOH)
-Substitution
[OH⁻] = antilog (-12.65)
-Result
[OH⁻] = 2.22 x 10⁻¹³
Hello there.
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Some elementary particles are positively or negatively
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b. charged particles.
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