Steven acquired a contract to create a museum that has a traditional appearance with rough textures. Which material can Steven u
1 answer:
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Answer:
a)
b)
Explanation:
From the properties of Super-heated Refrigerant 134a Vapor at ,
; we obtain the following properties for specific enthalpy and specific entropy.
So; specific enthalpy
specific entropy
Also; from the properties of saturated Refrigerant 134 a vapor (liquid - vapor). pressure table at ; we obtain the following properties:
Given that the power input to the compressor is 2 hp;
Then converting to Btu/hr ;we known that since 1 hp = 2544.4342 Btu/hr
2 hp = 2 × 2544.4342 Btu/hr
2 hp = 5088.8684 Btu/hr
The steady state energy for a compressor can be expressed by the formula:
By neglecting kinetic and potential energy effects; we have:
b) To determine the entropy generation; we employ the formula:
In a steady state condition
Hence;
Answer:
Following is attached the solution or the question given.
I hope it will help you a lot!
Explanation:
Answer:
Explanation:
Using equation of pure torsion
where
T is the applied Torque
is polar moment of inertia of the shaft
t is the shear stress at a distance r from the center
r is distance from center
For a shaft with
Outer Diameter
Inner Diameter
Applying values in the above equation we get
x
Thus from the equation of torsion we get
Applying values we get
T =829.97Nm
Answer:
Explanation:
The formula for critical stress is
K is the plane strain fracture toughness
Y is dimensionless parameters
We are to Determine the Critical stress
Now replacing the critical stress with 54.8
a with 0.2mm = 0.2 x 10⁻³
Y with 1
The fracture will not occur because this material can handle a stress of 2186.20Mpa before fracture. it is obvious that is greater than 2023Mpa
Therefore, the specimen does not failure for surface crack of 0.2mm