Answer:
E
Explanation:
A catalyst is a substance which alters the rate of a chemical reaction. We check for the correctness of each of the options as follows:
A. Is wrong.
A catalyst can increase the rate of the forward and backward reaction
B. Is wrong
A catalyst does not slow the reverse reaction only. This particular case is the case of a negative catalyst
C is wrong
A catalyst has no effect on the equilibrium nor the equilibrium constant
D is wrong
Catalyst has no effect on equilibrium value
E is correct
Although Catalysts has no effect on equilibrium or its constant value, it can increase the the rate at which equilibrium is achieved by speeding up the reaction through bringing down the activation energy
<span>When a large number of atoms of the same isotope are observed they will have a statistically consistent half life.
</span>An unstable nucleus contains a near excessive number of RNA chemical can spontaneously break apart into one or more nuclei all with a lighter state. #believe
Solution:
At the equivalence point, moles NaOH = moles benzoic acid
HA + NaOH ==> NaA + H2O where HA is benzoic acid
At the equivalence point, all the benzoic acid ==> sodium benzoate
A^- + H2O ==> HA + OH- (again, A^- is the benzoate anion and HA is the weak acid benzoic acid)
Kb for benzoate = 1x10^-14/4.5x10^-4 = 2.22x10^-11
Kb = 2.22x10^-11 = [HA][OH-][A^-] = (x)(x)/0.150
x^2 = 3.33x10^-12
x = 1.8x10^-6 = [OH-]
pOH = -log [OH-] = 5.74
pH = 14 - pOH = 8.26
dont know what the web looks like but mushrooms are decomposers
Answer is: n-octane.
Octane is the straight-chain alkane (an acyclic saturated hydrocarbon) with eight carbon atoms.
Carbons in octane have sp3 hybridization (carbon’s 2s and three 2p orbitals combine into four identical sp3 orbitals).
Orbitals in sp3 hybridization have a tetrahedral arrangement and form single (sigma) bonds.
Burning octane fuel is very fast chemical reaction, it happens in immediately.
Main products of the combustion of fossil fuels are carbon(IV) oxide and water.
Chemical reaction: C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O; ΔH = -5500 kJ/mol.
